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我期待在外部提供的模式下使用L6480,我的系统将提供: VS = + 24V DCVSREG / VCC = + 12V VCCREG / VREG = + 3.3V 在紧急停止条件下,系统提供给VS的+ 24V被移除(浮动)。 L6480可以处理这种情况,即VS和VBOOT被移除,但其他轨道仍分别提供+ 12V和+ 3.3V? 在数据表的第34页上有一个注释说明 当由于紧急停止条件而移除VS时,VSREG将比VBOOT(浮动)大+ 12V,导致内部保护二极管导通。 然而,它继续说没有方向,额定值的细节,也不会导致这种大的电压差导致不希望的操作。 这是我对二极管感到困惑的地方。关于方向,二极管的阳极连接到VSREG,阴极连接到VS. 在紧急停止条件期间,这将通过+ 12V,减去二极管的正向压降,到VS引脚和电荷泵,并尝试继续通过二极管从+ 12V电源为电机供电。使用二极管反向取向,VS较小的二极管正向电压将施加到VSREG + 12V,这违反了VSREG的7.5-15V限值。 当VS被移除时,我可以安全地使用没有二极管的L6480吗? 或者L6480不能在VS被移除的系统中使用? 谢谢, 布拉德 #l6480-电源 以上来自于谷歌翻译 以下为原文 Hello, I am looking at using the L6480 in the externally supplied modes, where my system will be supplying: VS = +24V DCVSREG/VCC = +12V VCCREG/VREG = +3.3V The +24V supplied to VS by the system is removed (floating) during an emergency stop condition. Can the L6480 handle this situation where VS and thus VBOOT is removed, but the other rails are still supplied with the +12V and +3.3V respectively? On page 34 of the data sheet there is a note that states When VS is removed due to an emergency stop condition, VSREG will be +12V greater than VBOOT (floating), causing the internal protection diode turnon. It goes on to say however there is no detail of direction, rating nor if this will cause undesired operation with such a large difference in voltage. This is where I am confused about the diode. Regarding direction, the diode would have the anode connected to VSREG and the cathode to VS. During the emergency stop condition this would pass the +12V, less the forward voltage drop of the diode, to the VS pins and charge pump, and try to continue to power the motor from the +12V supply via the diode.With the diode in the reversed orientation, VS less the diode forward voltage would be applied to the VSREG +12V which violates the 7.5-15V limit of VSREG. So can I SAFELY use the L6480 without diodes when VS is removed? Or the L6480 cannot be used in a system where VS is removed? Thanks, Brad #l6480-power-supply |
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3个回答
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保护二极管的阳极必须放在VSREG上,阴极放在VS上。您也可以使用EVAL6480H-DISC原理图作为参考。
这样,当移除24 V电源时,VS引脚通过12 V线保持高电平。一旦24 V电源恢复,VS引脚将恢复为24 V. 关于该二极管的反向额定电压,它只需要高于VS电源,因此30 V二极管就足够了。 以上来自于谷歌翻译 以下为原文 The protection diode must be put with the anode on VSREG and the cathode on VS. You can also use the EVAL6480H-DISC schematic as reference. In this way when the 24 V supply is removed the VS pin is kept high by the 12 V line. As soon as the 24 V supply is restored, the VS pin returns at 24 V. About the reverse voltage rating of this diode, it just need higher than VS supply, so a 30 V diode is enough. |
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谢谢 。
Poli.Enrico 这是我的担心,如果去掉24V电源并且功率级处于活动状态,则功率级将尝试继续通过二极管从12V轨道运行,从而导致二极管故障。 不幸的是,当移除24V时(通过紧急停止条件),我无法保证功率级处于非活动状态。 我正在考虑将VS电源与FET桥和L6480分开。 我能否为L6480 VS提供恒定的24V电压,但是对FET桥有保护电源吗? 因此,当移除24V时,它仅从FET桥中移除,而不是从L6480上的VS移除。 L6480试图在没有FET供电的情况下驱动FET的栅极是否存在问题? 注意:原始帖子包含大量线程对话,只能迁移到第9级 以上来自于谷歌翻译 以下为原文 Thanks . Poli.Enrico That was my concern, that if the 24V supply is removed AND the power stage is active, then the power stage will try to continue to operate from the 12V rail via the diode, resulting in diode failure. Unfortunately I cannot guarantee the power stage to be inactive when the 24V is removed (via emergency stop condition). I was thinking about separating the VS supplies from the FET bridge and the L6480. Could I supply the L6480 VS with constant 24V, but have the protected supply to the FET bridge? So when the 24V is removed, it is only removed from the FET bridges, not VS on the L6480. Is there an issue with the L6480 attempting to drive the gates of the FETs with no supply to the FETs? Note: the original post contained a large number of threaded conversations and was only able to be migrated to the 9th level |
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你好
Jensen.Brad •将功率级电源与IC的VS引脚去耦是不安全的;存在违反OUT引脚绝对额定值(-5 V至VBOOT)的风险。 您是否认为可以在移除电源之前强制重置设备?通过这种方式,所有MOSFET都将关闭,并且不可能使保护二极管过载。 注意:原始帖子包含大量线程对话,只能迁移到第9级 以上来自于谷歌翻译 以下为原文 Hi Jensen.Brad ‌It is not safe to decouple the power stage supply from the VS pin of the IC; there is the risk to violate the absolute ratings of the OUT pins (-5 V to VBOOT). Do you think it is possible to force a reset of the device just before removing the supply? In this way all the MOSFETs will be turned off and there will be no possibility to overstress the protection diode. Note: the original post contained a large number of threaded conversations and was only able to be migrated to the 9th level |
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