IHM01A1 L6474在有效输出期间复位引脚

我对董事会有一些疑问（也许你们中的任何人对电子产品有了更好的理解）。我使用带步进电机的电路板在直线驱动器上移动推车。移动将受到接近传感器的限制，该传感器激活我板上的中断。 （我使用Arduino板）。我使用45V和3A作为步进电机。编码时一切都还可以。但是当我尝试改进我的应用程序的代码时，我不小心弄乱了主板，情况是这样的：


1.在设置过程中，L6474库将被激活。电机将朝向接近传感器旋转。

2.通常在到达传感器后，将激活中断，然后执行HardStop（）功能。 （这段代码还可以。）

但是当我使用代码时，在中断激活后，我使用Reset（）函数而不是HardStop（）函数。 （愚蠢但虚假的错误）。之后它不再起作用了。我立即查看L6474数据表。它指出，当输出有效时，不建议重置设备。在电源显示器上，它不再显示45V，而是大约1.0V。

问题是，您认为芯片是否已损坏？通常情况下，如果芯片损坏，它会闻起来像烟雾或燃烧，但从外观上看，芯片看起来对我来说还不错。

提前致谢！
#ihm01a1＃l6474



以下为原文




I have some question regarding the board (maybe anyone of you have a better understanding on electronic). I use the board with stepper motor to moves a cart on the linear drives. The move will be limited by proximity sensor that activates the interrupt on my board. (I use Arduino board). I use 45V with 3A for my stepper motor. Everything was okay with the coding. But as I try to improve the code for my application, I'd accidentally mess up the board, The situation was like this:


1.During setup, the L6474 library will be activated.  And the motor will be rotates towards the proximity sensor.

2. Normally after reaching the sensor, interrupt will be activated and then the HardStop() function will be followed. (This code was ok.)

3. But as I play with the code, after the interrupt activates, I use the Reset() function instead of the HardStop() function. (Silly but dummy mistake). After that it didn't function anymore. I immediately check the L6474 datasheet. It states that it is not recommended to reset the device when outputs are active. On the power supply display, it didn't show 45V anymore but instead about 1,0 V.

4. The question is, did you think the chip is damaged? Normally if the chip are damaged, it would smell like a smoke or it burns, but from the appearance only, the chip looks ok for me.

Thanks in advance!  
#ihm01a1 #l6474