PNA-X/029噪声接收器集成时间是多少？

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     以下为原文

  Oops! I just fixed the help file. Thanks for letting us know.

积分时间取决于噪声带宽和噪声平均数（与信道扫描或点平均无关）。



     以下为原文

  the integration time depends on the noise bandwidth and the number of noise averages (which is independent of the channel sweep or point averaging).

我试图估计噪声设置中的测量误差，包括一个管理调谐器。
对于足够大的BW时间乘积，可以通过sigma（T）/ T = 1 / sqrt（Navg * BW * t）来估计误差。
这就是我推导出1ms积分时间的方法。
现在，如果积分时间也取决于带宽，则很难使用该等式。
你还有更多的量化信息吗？
或者积分时间与带宽成反比？
这样，增加带宽不会改善错误。
对不起，我目前无法访问我们的PNA-X，因此无法进行测试。



     以下为原文

  I am trying to estimate the measurement errors off our noise setup including a maury tuner.
For a sufficiently large BW-time product, the errors can be estimated by
sigma(T)/T = 1 / sqrt(Navg * BW * t).
This is how I derived the 1ms integration time.
Now if the integration time is also dependent on the bandwidth, it is difficult to use this equation.
Do you have any more quantitative information?
Or is the integration time inversely proportional to the bandwidth? This way increasing bandwidth does not improve the error.
I am sorry, I currently have no access to our PNA-X, so I am unable to perform tests.

我们有两个选项：028和029. 028使用VNA接收器和数字转换器，积分时间几乎正好是1 / BW，并且必须使用改善抖动平均值。
原始IF BW约为11 MHz，有效BW来自数字滤波器。
在数字滤波器之后，确定噪声功率，并且必须对其进行平均以消除抖动。
在029中，使用不同的接收器和数字转换器，并且数字转换器首先转换为功率（以高采样率）然后（我相信）对于每个“噪声采集”确实（相信）10,000个相同的平均值。
该接收器的BW由模拟滤波器（几个值，如4 MHz，8 MHz，24 MHz和一些较低的值）设置。
我认为你在采集时间上非常接近，数字转换器具有100纳秒的实际噪声测量速率，10,000的积分可以给你1毫秒的时间。
每个噪音平均值增加了10,000次收购。
这与IF BW无关。



     以下为原文

  We have two options: 028 and 029.  028 uses the VNA receiver and digitizer, and the intergration time is almost exactly 1/BW, and to improve jitter averaging must be used.  The raw IF BW is about 11 MHz, and the effective BW comes from the digital filter.  After the digital filter the noise power is determined, and must be averaged to remove jitter.

In 029, a different receiver and digitizer is used, and the digitizer first converts to power (at a high sample rate) and then does (I believe) 10,000 averages of the samels for each "noise acquisition".  The BW of this receiver is set by an analog filter (of a few values, like 4 MHz, 8 MHz, 24 MHz and some lower ones).  I think you are close on the acquision time,the digitizer has a real rate of 100 nsec noise measurement with the 10,000 integration to give your time of 1 msec.  Each noise average adds another 10,000 acquisitons.  This doesn't change with IF BW.