[问答]

不能读取stm8中的ADC1通道

问答对人有帮助，内容完整，我也想知道答案 0 亲爱的大家我试图在宇宙编译器中读取stm8中的ADC1通道，但我还是不能。只要主程序开始配置ADC1初始化没有任何反应。我不知道中断的问题是什么。构建器中没有错误。 hex文件出来了。 void ADC_CONFIG（void） { ADC1_DeInit（）; ADC1_Init（ADC1_CONVERSIONMODE_CONtiNUOUS，ADC1_CHANNEL_9，ADC1_PRESSEL_FCPU_D2，ADC1_EXTTRIG_GPIO，DISABLE， ADC1_ALIGN_RIGHT， ADC1_SCHMITTTRIG_CHANNEL9，DISABLE）; ADC1_Cmd（ENABLE）; ADC1_ITConfig（ADC1_IT_EOC，ENABLE）; ADC1_StartConversion（）; enableInterrupts（）; } 这是ADC1的配置代码。但不幸的是我看不到任何中断功能的结果。该计划已在此停止， @interrupt void handleADCInt（void） { GPIO_WriteHigh（GPIOD，GPIO_PIN_0）; if（ADC1_GetFlagStatus（ADC1_FLAG_EOC）== SET） { PRSC = ADC1_GetConversionValue（）; } ADC1_ClearFlag（ADC1_FLAG_EOC）; } 我在矢量文件中定义了中断函数。非常感谢您的帮助以上来自于谷歌翻译以下为原文 Dear all I tried to read ADC1 channels in stm8 in cosmic compiler, but still I could not. as far as the main program start to config the ADC1 initialization nothing happen. I do not know what the problem is with interrupts. there is no error in builder. hex files came out. void ADC_CONFIG(void) { ADC1_DeInit(); ADC1_Init(ADC1_CONVERSIONMODE_CONTINUOUS, ADC1_CHANNEL_9,ADC1_PRESSEL_FCPU_D2, ADC1_EXTTRIG_GPIO, DISABLE, ADC1_ALIGN_RIGHT, ADC1_SCHMITTTRIG_CHANNEL9,DISABLE); ADC1_Cmd(ENABLE); ADC1_ITConfig(ADC1_IT_EOC, ENABLE); ADC1_StartConversion(); enableInterrupts(); } here is the configuration codes for ADC1. but unfortunately I can not see any result in interrupt function. the program has stopped here, @interrupt void handleADCInt(void) { GPIO_WriteHigh(GPIOD, GPIO_PIN_0); if(ADC1_GetFlagStatus(ADC1_FLAG_EOC) == SET) { prsc=ADC1_GetConversionValue(); } ADC1_ClearFlag(ADC1_FLAG_EOC); } I have defined the interrupt function in vector file. many thanks for your help 0
2019-3-12 16:47:19　　评论淘帖0 邀请回答您可以邀请以下用户，快速回答问题 × wang21cj 该类别下有 44 个回答。邀请回答新星之火12138 该类别下有 41 个回答。邀请回答 chm5 该类别下有 39 个回答。邀请回答 hgimtk 该类别下有 33 个回答。邀请回答 HengDu 该类别下有 30 个回答。邀请回答 jghgfdssas 该类别下有 28 个回答。邀请回答 hwp0415229 该类别下有 28 个回答。邀请回答可口可甜该类别下有 26 个回答。邀请回答 kingnet6688 该类别下有 26 个回答。邀请回答颜刚YanG 该类别下有 26 个回答。邀请回答 zyh34997 该类别下有 25 个回答。邀请回答柱子图宁该类别下有 25 个回答。邀请回答 kingnet9999 该类别下有 25 个回答。邀请回答 jenny042 该类别下有 25 个回答。邀请回答 andyfly7 该类别下有 25 个回答。邀请回答麻酱该类别下有 25 个回答。邀请回答成长的小师弟该类别下有 24 个回答。邀请回答 gXDhn 该类别下有 24 个回答。邀请回答 jiangwenwen 该类别下有 24 个回答。邀请回答哼小曲该类别下有 24 个回答。邀请回答举报许佳相关推荐 • 如何使用ADC1通道和ADC2同时采集？ 1993 • 如何利用STM32F1的ADC1通道1来采样外部电压值并通过串口调试助手打印出来？ 3606 • 请问ADC1扫描模式的完成标记？ 1092 • 8通道ADC_SAR_SEQ最后4个通道无法读取低电压 1601 • 语音遥控器里面的程序能不能读取和写入？ 2665 • 如何使用ADC1的通道1进行AD转换呢 1230 • STM32H743用ADC1_INP2做单端模式，ADC1_INN2怎么接？ 375 • ADC注入通道采样触发只要启动ADC1或ADC2中的任意一个就可以吗？ 4147 • STM32f103 四通道做ADC采样，采样结果异常 3824 • STM32F407双ADC采样ADC1和ADC2的时钟同时打开ADC1不能工作 4880 1个回答

答案对人有帮助，有参考价值 0 嗨，在中断处理程序中，当ADC启用以产生多种中断时，您应首先调用/public/STe2ecommunities/mcu/Lists/stm81/group__ADC1__Exported__Functions.html&sharpga950279308ea4bca1e2e8e213376f31b9 （/public/STe2ecommunities/mcu/Lists/stm81/group__ADC1__Exported__Types.html&sharpgae9f96f201b80ec24da0d51dbdb1660ee ITPendingBit）找到当前的ADC中断源并分别处理每个。如果EOC是唯一的来源，则无需执行此调用。您可能认为它是EOC。如果中断源是EOC，则无需执行此操作 if（ADC1_GetFlagStatus（ADC1_FLAG_EOC）== SET）由于ADC中断，这个“if”始终为真。只需读取ADC值即可。然后你忘了重置ADC1_IT_EOC标志，ADC EOC中断挂起标志。因此，在一次ADC中断后，标志保持置1。对于CPU，中断似乎没有处理，因此它将阻止进一步的ADC EOC中断。读取值后，您处理了中断，只需要告诉CPU。使用无效 /public/STe2ecommunities/mcu/Lists/stm81/group__ADC1__Exported__Functions.html&sharpga2450f7bbab4cff6a76605b5278741715 （/public/STe2ecommunities/mcu/Lists/stm81/group__ADC1__Exported__Types.html&sharpgae9f96f201b80ec24da0d51dbdb1660ee ITPendingBit）使用参数ADC1_IT_EOC复位ADC EOC中断挂起标志。注意读取ADC值有可能会重置ADC1_IT_EOC 自动标志（怀疑）。我没有找那个。 HTH，约翰注意：原始帖子包含大量线程对话，只能迁移到第9级以上来自于谷歌翻译以下为原文 Hi, In the interrupt handler, when the ADC is enabled to generate several kinds of interrupts, you should first call /public/STe2ecommunities/mcu/Lists/stm81/group__ADC1__Exported__Functions.html&sharpga950279308ea4bca1e2e8e213376f31b9 (/public/STe2ecommunities/mcu/Lists/stm81/group__ADC1__Exported__Types.html&sharpgae9f96f201b80ec24da0d51dbdb1660ee ITPendingBit) to find the current ADC interrupt source and deal with each separately. If EOC is the only source, you do not need to do this call. You may assume it is EOC. If the interrupt source is EOC, there is no need to do if (ADC1_GetFlagStatus(ADC1_FLAG_EOC) == SET) Because of the ADC interrupt this 'if' is always true. Just read the ADC value and do stuff. Then you forgot to Reset the ADC1_IT_EOC flag, the ADC EOC interrupt pending flag. So after one ADC interrupt, the flag remains set. To the CPU, the interrupt seems not handled, so it will block further ADC EOC interrupts. After you read the value, you handled the interrupt and just need to tell the CPU. Use void /public/STe2ecommunities/mcu/Lists/stm81/group__ADC1__Exported__Functions.html&sharpga2450f7bbab4cff6a76605b5278741715 ( /public/STe2ecommunities/mcu/Lists/stm81/group__ADC1__Exported__Types.html&sharpgae9f96f201b80ec24da0d51dbdb1660ee ITPendingBit ) with parameter ADC1_IT_EOC to reset the ADC EOC interrupt pending flag. Note There is a possibility that reading the ADC value resets the ADC1_IT_EOC flag automaticaly (doubt it). I have not looked for that. HTH, John Note: the original post contained a large number of threaded conversations and was only able to be migrated to the 9th level

2019-3-12 17:06:38 评论举报赵阳