[问答]

向L6206添加低端过流保护的最简单方法是什么？

问答对人有帮助，内容完整，我也想知道答案 0 我正在设计一个带有L6206螺线管驱动器的电路板。我的电路板使用每个引脚最大3安培的连接器，所以我选择了6206，因为它能够使用外部电阻在高端设置保守的3安培关断限制。不幸的是，这些部件在低端没有过电流或短路保护。增加典型应用电路以保护低端的最佳，最简单的方法是什么？我最初使用该部件作为四个独立的半桥用于驱动电磁阀（因此高侧电流限制在每个电桥上的两个电磁阀之间分开），并且希望通过停用低侧开关来保护芯片，如果输出短路至12V电源。以下是一些想法： 1.低端检测电阻上的比较器，将使能引脚拉低，与高端过流关断引脚并联; 2. NPN晶体管悬挂在低端检测电阻上，将使能引脚拉低 3.基于芯片的解决方案，如L6506 我查看了应用程序节点 http://www.st.com/resource/en/application_note/cd00003789.pdf 作者提出类似于选项＆amp; sharp2的东西，但使用SCR，然后一次性。这些解决方案可能源于L6201-3缺少施密特触发器。由于L6206在使能引脚上具有施密特触发器，因此我假设在使能引脚上有一个简单的NPN牵引，在过流电平下选择检测电阻为0.7V，就可以了。我计划在每个半桥输出上增加一个小电感（10uH），以确保有足够的时间保护这种保护。这有必要吗？＃l6206＃current-limiting＃短路保护以上来自于谷歌翻译以下为原文 I am designing a board with L6206 drivers for solenoids. My board is using connectors with a 3-amp per pin maximum, so I chose the 6206 for its ability to set a conservative 3 amp shutdown limit on the high side using an external resistor. Unfortunately these parts do not have over-current or short protection on the low side. What is the best, simplest way to augment the typical application circuit for protection on the low side? I am using the part initially as four separate half-bridges for driving solenoids (so the high-side current limit is split between two solenoids on each bridge), and would like to protect the chip, by deactivating the low-side switches, if the output gets shorted to a 12V supply. Here are a couple ideas: 1. A comparator on a low-side sense resistor pulling the enable pin low alongside the high-side overcurrent shutdown pin; 2. An NPN transistor hanging off the low-side sense resistor, pulling the enable pin low 3. A chip-based solution such as the L6506 I looked at the app node http://www.st.com/resource/en/application_note/cd00003789.pdf where the author suggested something similar to option &sharp2, but using an SCR, and then a one-shot. These solutions probably stem from the lack of Schmitt triggers on the L6201-3. Since the L6206 has Schmitt triggers on the enable pins, I'm assuming a simple NPN tugging on the enable pin, with sense resistor chosen for 0.7V at the overcurrent level, would do the trick. I'm planning to add small inductance (10uH) to each half-bridge output to guarantee enough time for this protection to act. Is this necessary? #l6206 #current-limiting #short-circuit-protection 0
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答案对人有帮助，有参考价值 0 我认为使用检测电阻和比较器的解决方案更好，因为允许您使用更小的电阻值。事实上，NPN解决方案施加的0.7V阈值意味着约233mOhm的电阻器 - >负载接近3A限值时功耗为2 W。请注意这一点：当你保护对地短路时，电流将在检测电阻上再循环，产生一个负电压。分流电阻值越高，负电压越高。无论您选择何种解决方案，都要注意比较器/ NPN对负电压的稳健性。将少量感应串联添加到输出是一个好主意，特别是为了使短路保护更加稳健。以上来自于谷歌翻译以下为原文 I think the solution using the sense resistor and a comparator is the better one because allows you to use smaller resistor value. In fact the 0.7 V threshold imposed by the NPN solution implies a resistor of about 233 mOhm --> 2 W of power dissipation when the load approaches the 3 A limit. Please consider also this point: when you are protecting against the short to ground the current will recirculate on the sense resistor generating a negative voltage . The higher the shunt resistor value, the higher the negative voltage. Whatever the solution you select, take care of the robustness on the comparator/NPN to the negative voltages. Adding a small induction in series to to output is a good idea, in particular to make more robust the short circuit protection.

2018-10-24 11:22:08 评论举报刘璐