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您好,我正在试图弄清楚XC2V6000在上电时会消耗多少电流。
DS表示“VCCINT,VCCAUX和VCCO电源应逐渐上升,单调,不超过200μs,不低于50 ms。” 这意味着,如果VCCINT,VCCAUX和VCCO电源在225μs内达到最小电压值,那么在最坏的情况下FPGA将在225μs内消耗800 mA?提前感谢.Alberto 以上来自于谷歌翻译 以下为原文 Hello, I am trying to figure out how much current is going to be consumed by my XC2V6000 on power-up. The DS says that "The VCCINT, VCCAUX, and VCCO power supplies shall each ramp on, monotonically, no faster than 200 μs and no slower than 50 ms." This means, that if VCCINT, VCCAUX, and VCCO power supplies reaches the minimum voltage value in 225 μs, then the FPGA will consume 800 mA during 225 μs in the worst case? Thanks in advance. Alberto |
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嗨Alberto,表5的描述解释了这些值是“Virtex-II器件正确上电和配置所需的最小电流。”这意味着如果你的电源为XC2V6000提供的电流超过800mA,那么器件可能消耗
当前但不是必需的。 如果它超过最小值,它将不会损坏该部分。 最小值是设备启动和正确配置所需的值。 -------------------------------------------------- -----------------------不要忘记回答,kudo,并接受为解决方案.------------- -------------------------------------------------- ---------- 以上来自于谷歌翻译 以下为原文 Hi Alberto, The description for Table 5 explains that the values are "the minimum current required by Virtex-II devices for proper power on and configuration." Meaning that if you have a supply that gives more than 800mA for the XC2V6000 then device may consume that current but its not required. It won't damage the part if it comsumes more than the minimum. The minimum value is what the device needs to power on and configure correctly. ------------------------------------------------------------------------- Don’t forget to reply, kudo, and accept as solution. ------------------------------------------------------------------------- |
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