[问答]

在已经执行处理程序的情况下设置标志时为什么不会重新触发ADC中断处理程序？

问答对人有帮助，内容完整，我也想知道答案 0 我正在做一个项目，我在独立模式下同时使用 ADC1 和 ADC2，两个 ADC 的 JEOS 作为中断触发器。在中断处理程序中，我为当前控制器做了一些计算。样机代码如下： void ADC1_2_IRQHandler(void) { if (ADC1->ISR & ADC_ISR_JEOS) { ADC1->ISR = ADC_ISR_JEOS; { } } if (ADC2->ISR & ADC_ISR_JEOS) { ADC2->ISR = ADC_ISR_JEOS; { } } } ADC1 和 ADC2 的转换由 hrtimer（以不同频率）触发，因此可以在中断处理程序仍在运行时设置两个 ADC 的 JEOS 标志。我希望中断处理程序在完成后立即重新评估，因为它的 ISR 中仍然设置了一个标志。然而，这似乎并没有发生，只有在设置了新标志后才会触发中断处理程序。例如，ADC2 已完成其转换序列，因此它设置 JEOS -> 调用中断处理程序 -> 清除 ADC2 JEOS 标志 -> 开始进行控制器计算......现在 ADC1 已完成，因此它设置 ADC1 JEOS -> 控制器计算是完成 -> 退出处理程序，只有在再次触发 ADC2 JEOS 后才会返回，然后它会清除 ADC1 JEOS，并且现在看到它已设置。有谁知道这是预期的行为，还是我做错了什么？下面ADC的初始化： void MX_ADC1_Init(void) { ADC_MultiModeTypeDef multimode = {0}; ADC_AnalogWDGConfTypeDef AnalogWDGConfig = {0}; ADC_InjectionConfTypeDef sConfigInjected = {0}; /** Common config / hadc1.Instance = ADC1; hadc1.Init.ClockPrescaler = ADC_CLOCK_ASYNC_DIV4; hadc1.Init.Resolution = ADC_RESOLUTION_12B; hadc1.Init.DataAlign = ADC_DATAALIGN_RIGHT; hadc1.Init.GainCompensation = 0; hadc1.Init.ScanConvMode = ADC_SCAN_ENABLE; hadc1.Init.EOCSelection = ADC_EOC_SEQ_CONV; hadc1.Init.LowPowerAutoWait = DISABLE; hadc1.Init.ContinuousConvMode = DISABLE; hadc1.Init.NbrOfConversion = 1; hadc1.Init.DiscontinuousConvMode = DISABLE; hadc1.Init.DMAContinuousRequests = DISABLE; hadc1.Init.Overrun = ADC_OVR_DATA_OVERWRITTEN; hadc1.Init.OversamplingMode = DISABLE; if (HAL_ADC_Init(&hadc1) != HAL_OK) { Error_Handler(); } /* Configure the ADC multi-mode / multimode.Mode = ADC_MODE_INDEPENDENT; if (HAL_ADCEx_MultiModeConfigChannel(&hadc1, &multimode) != HAL_OK) { Error_Handler(); } /* Configure Analog WatchDog 1 / AnalogWDGConfig.WatchdogNumber = ADC_ANALOGWATCHDOG_1; AnalogWDGConfig.WatchdogMode = ADC_ANALOGWATCHDOG_SINGLE_INJEC; AnalogWDGConfig.Channel = ADC_CHANNEL_3; AnalogWDGConfig.ITMode = DISABLE; AnalogWDGConfig.HighThreshold = 2048 + AWD_OCP_SETTING_PFC; AnalogWDGConfig.LowThreshold = 2048 - AWD_OCP_SETTING_PFC; AnalogWDGConfig.FilteringConfig = ADC_AWD_FILTERING_NONE; if (HAL_ADC_AnalogWDGConfig(&hadc1, &AnalogWDGConfig) != HAL_OK) { Error_Handler(); } /* Configure Injected Channel / sConfigInjected.InjectedChannel = ADC_CHANNEL_3; sConfigInjected.InjectedRank = ADC_INJECTED_RANK_1; sConfigInjected.InjectedSamplingTime = ADC_SAMPLETIME_12CYCLES_5; sConfigInjected.InjectedSingleDiff = ADC_DIFFERENTIAL_ENDED; sConfigInjected.InjectedOffsetNumber = ADC_OFFSET_NONE; sConfigInjected.InjectedOffset = 0; sConfigInjected.InjectedNbrOfConversion = 2; sConfigInjected.InjectedDiscontinuousConvMode = DISABLE; sConfigInjected.AutoInjectedConv = DISABLE; sConfigInjected.QueueInjectedContext = DISABLE; sConfigInjected.ExternalTrigInjecConv = ADC_EXTERNALTRIGINJEC_HRTIM_TRG2; sConfigInjected.ExternalTrigInjecConvEdge = ADC_EXTERNALTRIGINJECCONV_EDGE_RISING; sConfigInjected.InjecOversamplingMode = DISABLE; if (HAL_ADCEx_InjectedConfigChannel(&hadc1, &sConfigInjected) != HAL_OK) { Error_Handler(); } /* Configure Injected Channel / sConfigInjected.InjectedChannel = ADC_CHANNEL_6; sConfigInjected.InjectedRank = ADC_INJECTED_RANK_2; sConfigInjected.InjectedSamplingTime = ADC_SAMPLETIME_6CYCLES_5; sConfigInjected.InjectedSingleDiff = ADC_SINGLE_ENDED; if (HAL_ADCEx_InjectedConfigChannel(&hadc1, &sConfigInjected) != HAL_OK) { Error_Handler(); } } / ADC2 init function / void MX_ADC2_Init(void) { ADC_AnalogWDGConfTypeDef AnalogWDGConfig = {0}; ADC_InjectionConfTypeDef sConfigInjected = {0}; ADC_ChannelConfTypeDef sConfig = {0}; /* Common config / hadc2.Instance = ADC2; hadc2.Init.ClockPrescaler = ADC_CLOCK_ASYNC_DIV4; hadc2.Init.Resolution = ADC_RESOLUTION_12B; hadc2.Init.DataAlign = ADC_DATAALIGN_RIGHT; hadc2.Init.GainCompensation = 0; hadc2.Init.ScanConvMode = ADC_SCAN_ENABLE; hadc2.Init.EOCSelection = ADC_EOC_SEQ_CONV; hadc2.Init.LowPowerAutoWait = DISABLE; hadc2.Init.ContinuousConvMode = DISABLE; hadc2.Init.NbrOfConversion = 1; hadc2.Init.DiscontinuousConvMode = DISABLE; hadc2.Init.ExternalTrigConv = ADC_EXTERNALTRIG_HRTIM_TRG1; hadc2.Init.ExternalTrigConvEdge = ADC_EXTERNALTRIGCONVEDGE_RISING; hadc2.Init.DMAContinuousRequests = DISABLE; hadc2.Init.Overrun = ADC_OVR_DATA_OVERWRITTEN; hadc2.Init.OversamplingMode = ENABLE; hadc2.Init.Oversampling.Ratio = ADC_OVERSAMPLING_RATIO_16; hadc2.Init.Oversampling.RightBitShift = ADC_RIGHTBITSHIFT_NONE; hadc2.Init.Oversampling.TriggeredMode = ADC_TRIGGEREDMODE_SINGLE_TRIGGER; hadc2.Init.Oversampling.OversamplingStopReset = ADC_REGOVERSAMPLING_CONTINUED_MODE; if (HAL_ADC_Init(&hadc2) != HAL_OK) { Error_Handler(); } /* Configure Analog WatchDog 1 / AnalogWDGConfig.WatchdogNumber = ADC_ANALOGWATCHDOG_1; AnalogWDGConfig.WatchdogMode = ADC_ANALOGWATCHDOG_SINGLE_INJEC; AnalogWDGConfig.Channel = ADC_CHANNEL_1; AnalogWDGConfig.ITMode = DISABLE; AnalogWDGConfig.HighThreshold = 2048 + AWD_OCP_SETTING_HB; AnalogWDGConfig.LowThreshold = 2048 - AWD_OCP_SETTING_HB; AnalogWDGConfig.FilteringConfig = ADC_AWD_FILTERING_NONE; if (HAL_ADC_AnalogWDGConfig(&hadc2, &AnalogWDGConfig) != HAL_OK) { Error_Handler(); } /* Configure Injected Channel / sConfigInjected.InjectedChannel = ADC_CHANNEL_1; sConfigInjected.InjectedRank = ADC_INJECTED_RANK_1; sConfigInjected.InjectedSamplingTime = ADC_SAMPLETIME_12CYCLES_5; sConfigInjected.InjectedSingleDiff = ADC_DIFFERENTIAL_ENDED; sConfigInjected.InjectedOffsetNumber = ADC_OFFSET_NONE; sConfigInjected.InjectedOffset = 0; sConfigInjected.InjectedNbrOfConversion = 3; sConfigInjected.InjectedDiscontinuousConvMode = DISABLE; sConfigInjected.AutoInjectedConv = DISABLE; sConfigInjected.QueueInjectedContext = DISABLE; sConfigInjected.ExternalTrigInjecConv = ADC_EXTERNALTRIGINJEC_HRTIM_TRG4; sConfigInjected.ExternalTrigInjecConvEdge = ADC_EXTERNALTRIGINJECCONV_EDGE_RISING; sConfigInjected.InjecOversamplingMode = DISABLE; if (HAL_ADCEx_InjectedConfigChannel(&hadc2, &sConfigInjected) != HAL_OK) { Error_Handler(); } /* Configure Injected Channel / sConfigInjected.InjectedChannel = ADC_CHANNEL_3; sConfigInjected.InjectedRank = ADC_INJECTED_RANK_2; sConfigInjected.InjectedSamplingTime = ADC_SAMPLETIME_6CYCLES_5; sConfigInjected.InjectedSingleDiff = ADC_SINGLE_ENDED; if (HAL_ADCEx_InjectedConfigChannel(&hadc2, &sConfigInjected) != HAL_OK) { Error_Handler(); } /* Configure Injected Channel / sConfigInjected.InjectedChannel = ADC_CHANNEL_5; sConfigInjected.InjectedRank = ADC_INJECTED_RANK_3; if (HAL_ADCEx_InjectedConfigChannel(&hadc2, &sConfigInjected) != HAL_OK) { Error_Handler(); } /* Configure the injected channel to be monitored by WatchDog 2 or 3 / AnalogWDGConfig.WatchdogNumber = ADC_ANALOGWATCHDOG_3; AnalogWDGConfig.WatchdogMode = ADC_ANALOGWATCHDOG_SINGLE_REG; AnalogWDGConfig.Channel = ADC_CHANNEL_3; AnalogWDGConfig.HighThreshold = 3441; AnalogWDGConfig.LowThreshold = 0; if (HAL_ADC_AnalogWDGConfig(&hadc2, &AnalogWDGConfig) != HAL_OK) { Error_Handler(); } /* Configure the injected channel to be monitored by WatchDog 2 or 3 / AnalogWDGConfig.WatchdogMode = ADC_ANALOGWATCHDOG_SINGLE_REG; AnalogWDGConfig.Channel = ADC_CHANNEL_5; if (HAL_ADC_AnalogWDGConfig(&hadc2, &AnalogWDGConfig) != HAL_OK) { Error_Handler(); } /* Configure Regular Channel */ sConfig.Channel = ADC_CHANNEL_VOPAMP2; sConfig.Rank = ADC_REGULAR_RANK_1; sConfig.SamplingTime = ADC_SAMPLETIME_24CYCLES_5; sConfig.SingleDiff = ADC_SINGLE_ENDED; sConfig.OffsetNumber = ADC_OFFSET_NONE; sConfig.Offset = 0; if (HAL_ADC_ConfigChannel(&hadc2, &sConfig) != HAL_OK) { Error_Handler(); } } 0
2023-1-17 06:30:20　　评论淘帖0 邀请回答您可以邀请以下用户，快速回答问题 × wang21cj 该类别下有 47 个回答。邀请回答 chm5 该类别下有 44 个回答。邀请回答新星之火12138 该类别下有 42 个回答。邀请回答 hgimtk 该类别下有 36 个回答。邀请回答 HengDu 该类别下有 31 个回答。邀请回答可口可甜该类别下有 30 个回答。邀请回答 hwp0415229 该类别下有 30 个回答。邀请回答麻酱该类别下有 28 个回答。邀请回答 andyfly7 该类别下有 28 个回答。邀请回答 jghgfdssas 该类别下有 28 个回答。邀请回答 jiangwenwen 该类别下有 28 个回答。邀请回答 kingnet6688 该类别下有 28 个回答。邀请回答云汉007 该类别下有 27 个回答。邀请回答颜刚YanG 该类别下有 27 个回答。邀请回答柱子图宁该类别下有 27 个回答。邀请回答 bluepink 该类别下有 27 个回答。邀请回答法规处发该类别下有 27 个回答。邀请回答 ldliu 该类别下有 27 个回答。邀请回答成长的小师弟该类别下有 27 个回答。邀请回答 gXDhn 该类别下有 26 个回答。邀请回答举报张玉珍相关推荐 • 在中断处理子程序里，程序还没处理完能执行再次使能该中断吗 6025 • 在中断处理子程序里，程序还没处理完又使进入中断，请问该中断下面语句还会执行吗？ 7246 • 执行IRQ处理程序时可能会设置UART溢出标志，如何避免？ 478 • MPC5748G如何一次只为一个通道生成ADC EOC中断？ 482 • 什么是中断？中断处理程序原理是什么？ 2092 • ADC转换从第一个事件开始，然后在没有定时器事件的情况下连续发生的原因？ 333 • PSOC5LP中断处理中的抖动 1389 • 请问中断和主函数的处理 3709 • 关于定时器中断的问题 424 • 定时器在进入中断处理函数后，在执行中断函数的时候定时器是不是也在同时进行计数？ 5355 1个回答

答案对人有帮助，有参考价值 0 不太确定。这与应该发生的事情背道而驰。我会检查勘误表并仔细检查您对正在发生的事情的假设。

2023-1-17 11:19:21 评论举报李鸾