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嗨,我可以使用标准的N型校准装置来校准高达18 GHz的所有方式吗?
通常我会在S11测量中离开多远,这只是我所关注的。 谢谢。 以上来自于谷歌翻译 以下为原文 Hi, can I use standard type N calibration set to calibtate all the way up to 18 GHz? Typically how far would I be off on S11 measurement, which is only what I am concerned with. Thanks. |
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> {quote:title = joonlee95写道:} {quote}>嗨,>我可以使用标准的N型校准集来校准高达18 GHz的所有方式吗?
通常我会在S11测量中离开多远,这只是我所关注的。 >谢谢。 “标准N型校准装置”是什么意思? 有许多不同的型号,Agilent 85054B(标准)和85054D(经济型)均为18 GHz。 85032B的额定频率为6 GHz,85032F至9 GHz ...... 85054B非常昂贵。 你需要说明你的校准套件的型号,最好是你的VNA。 根据我的理解,两个最重要的错误是:* 1)负载的回波损耗。*为了获得最佳性能,您需要滑动负载,但经济型校准套件没有它们,所以我认为对于不太准确的测量 不需要它们。 使用Agilent 909F负载(如果您还没有它们)将是明智的。 * 2)打开的边缘电容。*如果您使用像我所拥有的85032B这样的套件,我*怀疑*多项式拟合在18 GHz时是有用的。 * IF *我的6 GHz套件可以让我在18 GHz时获得好运,*个人*我很想通过使用多项式系数来计算6 GHz两个开口的边缘电容,并假设它们在上面是常数 6 GHz。 换句话说,让我们假设多项式指示在6 GHz处,女性开放的边缘电容为120 fF,而男性开放则为64 fF,那么我很想定义一个用户校准套件:C0 = 120,C1 = 0,C2 = 0,C3 = 0。 OPEN(M)C0 = 64,C1 = 0,C2 = 0,C3 = 0。 打开(F)这可能会出现可怕的错误,但我的猜测是,它依赖于开放的多项式系数在18 GHz时是好的。 至于你能得到什么准确性,我真的不知道。 我认为短裤不会产生太大的影响。 您可能需要考虑从85054B校准套件(部件85054-60027和85054-60028)购买两个开口,使用您已有的短裤,并定义一个两者混合的校准套件。 这将是我的首选方法。 如果您的套件带有额定频率为18 GHz的负载,那么6 GHz 85032B校准套件中的负载也是如此,我认为可以。 Dave PS,“网络分析仪 - 校准/纠错”是应该发布此类问题的地方,但我确信同一群人阅读不同的VNA论坛。 以上来自于谷歌翻译 以下为原文 > {quote:title=joonlee95 wrote:}{quote} > Hi, > can I use standard type N calibration set to calibtate all the way up to 18 GHz? Typically how far would I be off on S11 measurement, which is only what I am concerned with. > Thanks. What do you mean by a "standard type N calibration set" ? There are numerous different models, and the Agilent 85054B (standard) and 85054D (economy) are both rated to 18 GHz. The 85032B is rated to 6 GHz, the 85032F to 9 GHz.. The 85054B is pretty damm expensive. You would need to state the model of your cal kit, and preferably your VNA too. From my understanding, the two most significant errors would be: *1) The return loss of the loads.* For optimal performance you want sliding loads, but economy cal kits don't have them, so I assume that for less accurate measurements you don't need them. Using Agilent 909F loads if you don't already have them would be sensible. *2) The fringing capacitance of the open.* If you take a kit like the 85032B that I have, I *suspect* that the polynomial fit would be alful at 18 GHz. *IF* I was going to chance my luck at 18 GHz with my 6 GHz kit, *personally* I'd be tempted to calculate the fringing capacitance of the two opens at 6 GHz by using the polynomial coefficients and assume they are constant above 6 GHz. In other words, lets assume the polynomials indicate at 6 GHz the fringing capacitance are 120 fF for the female open and 64 fF for the male open, then I'd be tempted to define a user cal kit with: C0=120, C1=0, C2=0, C3=0. OPEN(M) C0=64, C1=0, C2=0, C3=0. OPEN(F) That might go horribly wrong, but my guess is it would be better than relying on the polynomial coefficents of the open being OK at 18 GHz. As for what accuracy you could get, I really don't know. I don't think the shorts will make too much difference. You might want to consider buying the two opens from the 85054B cal kit (parts 85054-60027 and 85054-60028), using the shorts you already have, and defining a cal kit which is a mix of the two. That would be my preferred approach. If your kit comes with loads rated to 18 GHz, as are those in the 6 GHz 85032B cal kit, I would think that would be OK. Dave PS, the "Network Analyzers - Calibration/Error Correction" is where such questions should be posted, but I'm sure the much the same group of people read the different VNA forums. |
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