怎么使用AC信号馈送PSoC

大家好，
有人能帮我解决这个问题吗？
谢谢你的反馈！



     以下为原文
  Hi everyone,
     
     Could someone help me with this issue?
     
    Thanks for your feedbacks!

查看下面的博客文章。让我知道这是否有帮助。
HTTP://www. CyPress？COM/？RID＝50815和cAMP＝0
最好的问候，
加内什



     以下为原文
  Check out the below blog post.  Let me know if this helps.
   
    http://www.cypress.com/?rID=50815&cache=0
     
    Best Regards,
    Ganesh

你好，
谢谢你的帖子！它帮助了我。现在，我将AGND（ReFMUX的输出）连接到电路的GND（用于在所有部件中产生相同的AGND，正如它在文章中所说）。然后，我把信号在NANIN中的信号AC连接到ANSAMP和电路的AGND到IV（它是否与直接连接到RIFMUX的输出相同，不是吗？）.
我也想问一下，如果我在LCD中看到的结果（使用iSAMP和ADCVRR）我必须减去2.5来获得真正的值吗？由于所有电路考虑了2.5的AGND，所以它在PSoC中存在一个移动真实信号的直流分量来处理它。
你能告诉我我的方向是否正确吗？
谢谢你的反馈！
当做，



     以下为原文
   Hi graa,
     
    thank you for your post! It helped me. Now I connected the AGND (output of RefMux) to the gnd of the circuit (for making the same AGND in all parts, as it said in the post). Then, I have connected the signal AC in the pin NOINV the INSAMP and the AGND of the circuit to INV (will it be the same as connected directly to the output of Refmux, isn't?).
    I would like to ask you also, if the result I saw in the LCD (using INSAMP and ADCINVR) I have to subtract 2.5 to obtain the real value? Because, all circuit considers AGND of 2.5 so, is like it existed a DC component that move the real signal to treat it in the PSoC.
     
    Could you tell me if I'm in the right direction?
     
    Thanks for your feedbacks!
    Regards,

如果输入信号是从地面的PSoC，VSS隔离那么是的，你是在正确的方向连接输入信号PSoC。
对于ADC的输出和2.5voffset，如果设置了ADC的数据格式为“签名”，与AGND合作的adcwill作为参考。例如，如果输入的交流信号为0V，那么ADCoutput将是0，如果输入信号+ VE、ADC输出将+ VE。如果输入信号是VE、adcoutput将2的恭维我。因此，您不必从ADCValk中减去任何值。
最好的问候，
加内什



     以下为原文
  If the ground of the input signal is isolated from the VSS of the PSoC, then yes, you are in the right direction in connecting the input signal to the PSoC.
     
    Regarding the ADC output and the 2.5V offset, if you set the ADC's Data Format to "Signed", the  the ADC will work with AGND as the reference.  ie, if the input AC signal is 0V, then ADC output will be 0, if input signal is +ve, ADC output will be +ve.  if input signal is -ve, ADC output will be 2's compliment -ve.  So, you do not have to subtract any value from the ADC value.
     
    Best Regards,
    Ganesh

嗨，Graa，
谢谢您的确认。
我问过你（下面是2，5），因为我使用的是iSAMP，3-OPAM，我在这个模块的数据表中看到，输出将是：VADND+G*（VDIFF），所以，就像信号总是与这个偏移…这个等式使我认为，也许在信号输出或我在LCD中看到的值是用2，5增加的。但是，我看到配置2-opAM有一个VREF，但是，在这种情况下，你可以选择引用，不是吗？
哪一种处理小电压交流信号更好？使用一个或另一个有很多不同之处吗？
谢谢你的回复！
当做，



     以下为原文
  Hi Graa,
     
    thanks for your confirmation.
    I asked you this (substract 2,5) because I'm using the INSAMP, 3-OPAM, and I saw in the datasheet of this module that the output will be: Vagnd+G*(Vdiff) so, is like the signal always goes with this offset... This equation made me think that perhaps in the signal output or the value I was seeing in the LCD was with 2,5 added. However, I saw that the configuration 2-OPAM has an Vref added but, in this case you can choose the reference, isnt?
    Which one is better to treat an small voltage AC signal? There are a lot of difference in using one or other?
    Thanks for your reply!
     
    Regards,