STM是否在HALT0模式下运行？

你好，
我们在SPC560P44L3上的应用在空闲回路中切换到HALT0模式以节省功耗。 PIT配置为每毫秒唤醒CPU以处理定时器，这很好。
现在我想配置自由运行的STM以保持高时间，但似乎在HALT0状态期间STM计数器不会递增。
遗憾的是，我无法提供小型测试程序，因为事件处理，定时器和省电的逻辑分散在整个项目中。基本上我要做的是重现这个：
为1Khz定时器中断编程PIT读取STM定时器 - ＆gt; t1通过执行SetRunMode（SPC5_RUNMODE_HALT0）等待中断读取STM计时器 - ＆gt; t2System时钟设置为16MHz，STM分频器设置为1，所以我期望（t2-t1）为16e6 / 1000 = 16e3。相反，这个数字要小得多，而且各不相同。但是，如果我将使用SetRunMode（）的行更改为asm（'wait'），则结果与预期完全一致。
HALT0模式配置如下：
#define SPC5_ME_HALT0_MC_BITS（0UL | SPC5_ME_MC_MVRON | SPC5_ME_MC_DFLAON_LP | SPC5_ME_MC_CFLAON_LP | SPC5_ME_MC_IRCON | SPC5_ME_MC_PLL0ON | SPC5_ME_MC_XOSC0ON | SPC5_ME_MC_IRCON | SPC5_ME_MC_SYSCLK_FMPLL0）
我可能在数据表中遗漏了关于STM时钟门控的内容，但是我找不到一个用于关闭STM时钟的ME_PCTLx寄存器。
任何提示非常感谢，



以下为原文




Hello,
Our application on the SPC560P44L3 switches to HALT0 mode in the idle loop for power saving. The PIT is configured to wakeup the CPU every msec for handling timers, which works just fine.
Now I'd like to configure the free running STM for highres time keeping, but it seems that during HALT0 state the STM counter does not increment.
Unfortunately I'm not able to provide a small test program, as the logic for event handling, timers and power saving is scattered throughout the project. Basically what I do to reproduce this is:

• Program the PIT for 1Khz timer interrupts
• Read STM timer -> t1
• Wait for interrupts by doing SetRunMode(SPC5_RUNMODE_HALT0)
• Read STM timer -> t2
  

System clock is set to 16MHz, STM divider to 1, so I'd expect (t2-t1) to be 16e6/1000 = 16e3. Instead, the number is much smaller and varies. If however I change the line with SetRunMode() to asm('wait'), the results are exactly as expected.
HALT0 mode is configured like this:
#define SPC5_ME_HALT0_MC_BITS               (0UL | SPC5_ME_MC_MVRON | SPC5_ME_MC_DFLAON_LP | SPC5_ME_MC_CFLAON_LP | SPC5_ME_MC_IRCON | SPC5_ME_MC_PLL0ON | SPC5_ME_MC_XOSC0ON | SPC5_ME_MC_IRCON | SPC5_ME_MC_SYSCLK_FMPLL0)
I'm probably missing something in the datasheet about clock gating to the STM, but I'm not able to find a ME_PCTLx register which gates the STM clock.
Any hints much appreciated,