FPGA内存位怎么计算

i，您想要计算多种内存？BRAM列在数据表中，作为设备中所有BRAM的最大值（按部件号）。
请记住，总位数= 1024 *“Mbytes”指定（K = 024位用于存储器规格）。您使用的BRAM多少取决于您的设计使用多少BRAM块。
该信息位于综合，布局和布线工具提供的设备使用报告中。配置存储器或CRAM是用于配置（或重新配置）设备的存储器。要估计CRAM大小，您可以采用总数。
比特流大小（来自datsasheets），减去BRAM大小，并占用该数字的90％（比特流的~10％是命令，而不是内容）。
Austin Lesea主要工程师Xilinx San Jose



以下为原文

i,

There is more than one kind of memory, which do you want to count?

The BRAM is listed in the datasheets, as a maximum for all the BRAM in the device (by part number).  Remember that total number of bits = 1024 * "Mbytes" specified (K=024 bits for memory specification).

How much of the BRAM you use depends on how many BRAM blocks are used by your design.  That information is in the device usage reports provided by the synthesis, place and route tools.

Configuration memory, or CRAM, is the memory which is used to configure (or reconfigure) the device.

To estimate the CRAM size, you may take the total bitstream size (from the datsasheets), subtract the BRAM size, and take 90% of that number (~10% of the bitstream are commands, and not contents).
Austin Lesea
Principal Engineer
Xilinx San Jose

在产品简介中可能不太清楚的是18Kb和36Kb的块是真的
计算相同的资源。
例如，对于V6，您可以在表格中看到：
显示最小部分312 18Kb和156 36Kb块RAM。
实际上只有156个内存
块，每个块可配置为2 x 18 Kb或1 x 36 Kb，最大（Kb）列将
显示总块RAM位，在这种情况下与156 x 36 Kb相同。
你不添加18Kb和
36Kb柱。
Max Kb列显示设备中实际的Block RAM位总数。
对于显示它的设备，总分布式存储器不是块RAM位总数的一部分。
-  Gabor
-  Gabor



以下为原文

What may not be so clear in the product brief is that the 18Kb and 36Kb blocks are really
counting the same resources.  So for example for V6 you can see in the table:
 

 
showing for the smallest part 312 18Kb and 156 36Kb block RAMs.  In reality there are only 156 memory
blocks, each of which can be configured as either 2 x 18 Kb or 1 x 36 Kb, and the Max (Kb) column will
show the total block RAM bits, which is the same as 156 x 36 Kb in this case.  You do not add the 18Kb and
36Kb columns.  The Max Kb column shows the actual total number of block RAM bits in the device.
 
The total distributed memory, for devices that show it, is not part of the block RAM bits total.
 
-- Gabor
-- Gabor

Gabor，关于18Kb和36 Kb BRAM（同一块的两种模式）的好点。分布式RAM是查找表，用作RAM，是比特流配置存储器（CRAM）的一部分。
Austin Lesea主要工程师Xilinx San Jose



以下为原文

Gabor,

Good point about the 18Kb, and 36 Kb BRAMs (two modes of the same block).

Distributed RAM are the look up tables, used as RAM, and are part of the bitstream configuration memory (CRAM).Austin Lesea
Principal Engineer
Xilinx San Jose

非常感谢Gabor和Austin。
解释和答案都很棒。



以下为原文

Thanks a lot Gabor and Austin. Both Explanations and answers are great.