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#include
***it ADDR0 = P1^0; ***it ADDR1 = P1^1; ***it ADDR2 = P1^2; ***it ADDR3 = P1^3; ***it ENLED = P1^4; unsigned char code led[] = {0xc0, 0xf9, 0xa4, 0xb0, 0x99, 0x92, 0x82, 0xf8, 0x80, 0x90}; unsigned char ledbuff[] = {0xff, 0xff, 0xff, 0xff, 0xff, 0xff}; unsigned long sec = 0, sec1; unsigned int cnt = 0; unsigned char flag = 0, i = 5, aa[6], b; void main() { ENLED = 0; ADDR3 = 1; TMOD = 0x01; TH0 = 0xfc; TL0 = 0x66; EA = 1; ET0 = 1; TR0 = 1; while (1) { if (flag == 1) { flag = 0; sec++; } aa[0] = sec % 10; aa[1] = sec / 10 % 10; aa[2] = sec / 100 % 10; aa[3] = sec / 1000 % 10; aa[4] = sec / 10000 % 10; aa[5] = sec / 100000 % 10; for (b=5; b>0; b--) { if (aa == 0) { ledbuff = 0xff; } else { break; } } for ( ; b>=0; b--) { ledbuff = led[aa]; } } } void interrupttimer() interrupt 1 { TH0 = 0xfc; TL0 = 0x66; cnt++; if (cnt == 1000) { cnt = 0; flag = 1; } P0 = 0xff; switch (i) { case 5: ADDR2 = 1; ADDR1 = 0; ADDR0 = 1; P0 = ledbuff[5]; i--; break; case 4: ADDR2 = 1; ADDR1 = 0; ADDR0 = 0; P0 = ledbuff[4]; i--; break; case 3: ADDR2 = 0; ADDR1 = 1; ADDR0 = 1; P0 = ledbuff[3]; i--; break; case 2: ADDR2 = 0; ADDR1 = 1; ADDR0 = 0; P0 = ledbuff[2]; i--; break; case 1: ADDR2 = 0; ADDR1 = 0; ADDR0 = 1; P0 = ledbuff[1]; i--; break; case 0: ADDR2 = 0; ADDR1 = 0; ADDR0 = 0; P0 = ledbuff[0]; i=5; break; default : break; } } 这个程序是数码管高位位零时不显示,怎么不对啊,求解 |
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3个回答
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for ( ; b>=0; b--)
{ ledbuff = led[aa]; } 这句有问题,我把b定义为unsigned char型,b就一直大于0零,不能小于零,所以这就成了一个死循环。 昨晚找了好久才找出来! |
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