如何用PIC18F97J60 100引脚MCU设计新设备

MCU是否需要额外的“魔法”来激活USAT？我不知道这是否重要，但是我在MPLLABX中打开了sourcepic18plibUSART1open.c文件，并且没有定义“EAUSART_Vx”，所以一切都是灰色的（非活动的）。当我使用Open1USAT（）函数时，我想知道是否有关联。但是我已经复制并改写了一个版本的代码到我的.c，步进式调试器，以确保它被执行并且没有任何…每秒钟调用一个字母7AuthART（a）似乎不起作用。我有一个UART / USB转换器，它闪烁着红色LED当我发送个人电脑和绿色LED时，MCU响应。不幸的是，只能看到红色的LED。



      以下为原文

    Is there any additional "magic" needed in that MCU to activate USART?
 
I don't know if it matters but I have opened sourcespic18plibUSARTu1open.c file in MPLAB X and none of "EAUSART_Vx" was defined so everything was grey (inactive). I wonder if anything is linked when I use Open1USART() function. But I have copied and renamed code of one version to my main.c, stepped into
Open7USART(USART_TX_INT_OFF & USART_RX_INT_OFF &

USART_ASYNCH_MODE & USART_EIGHT_BIT &

USART_BRGH_HIGH & USART_ADDEN_OFF &

USART_CONT_RX, 162); //9600@25MHz
 
in debugger to be sure it's executed and nothing... Write7USART('a') called every second doesn't seem to work. I have an UART/USB converter and it blinks with red LED when I send somenthing from PC and with green LED when MCU responds. Unfortunately only red LED can be seen.
 

void Open7USART( unsigned char config, unsigned int spbrg)
{
  TXSTA1 = 0;          // Reset USART registers to POR state
  RCSTA1 = 0;
 
  if(config&0x01)      // Sync or async operation
    TXSTA1bits.SYNC = 1;

  if(config&0x02)      // 8- or 9-bit mode
  {
    TXSTA1bits.TX9 = 1;    
    RCSTA1bits.RX9 = 1;
  }

  if(config&0x04)      // Master or Slave (sync only)
    TXSTA1bits.CSRC = 1;

  if(config&0x08)      // Continuous or single reception
    RCSTA1bits.CREN = 1;
  else
    RCSTA1bits.SREN = 1;

  if(config&0x10)      // Baud rate select (asychronous mode only)
    TXSTA1bits.BRGH = 1;
 
  if(config&0x20)      // Address Detect Enable
    RCSTA1bits.ADDEN = 1;
   
 
  if(config&0x40)      // Interrupt on receipt
    PIE1bits.RC1IE = 1;
  else
    PIE1bits.RC1IE = 0;

  if(config&0x80)      // Interrupt on transmission
    PIE1bits.TX1IE = 1;
  else
    PIE1bits.TX1IE = 0;

  SPBRG1 = spbrg;       // Write baudrate to SPBRG1
  SPBRGH1 = spbrg >> 8; // For 16-bit baud rate generation

  TXSTA1bits.TXEN = 1;  // Enable transmitter
  RCSTA1bits.SPEN = 1;  // Enable receiver
  TRISCbits.TRISC6 = 0;
  TRISCbits.TRISC7 = 1;
  if(TXSTA1bits.SYNC && !TXSTA1bits.CSRC)    //synchronous  slave mode
        TRISCbits.TRISC6 = 1;
}

void Write7USART(char data)
{
  if(TXSTA1bits.TX9)  // 9-bit mode?
  {
    TXSTA1bits.TX9D = 0;       // Set the TX9D bit according to the
    if(USART1_Status.TX_NINE)  // USART1 Tx 9th bit in status reg
      TXSTA1bits.TX9D = 1;
  }

  TXREG1 = data;      // Write the data byte to the USART1
}

 

好吧，我在自言自语，但是我再向前一步。新的，闪亮的一天已经来到，我的DSO波形出现在TX线上。因为默认情况下我使用了AND掩码，所以在baud1UART()中漏掉了一些参数，所以波形被反转了，但是经过快速调整，现在可以了，我每秒都得到“a”。在哪里可以找到像“voidinter.SerialRxPinInter.()”这样的描述？在前面提到的示例代码中，但是现在它似乎没有被调用，并且在字符接收之后设备冻结，所以我猜ISR应该被不同地调用（？）编辑：我已经在数据表中挖掘过，我发现这个名字“无效中断SerialRxPin中断（））是误导性的。在另一个例子中，我已经“空中断Time0OffFuffE（）”，但是在这个MCU中没有单独的ISR。对于高优先级和低优先级中断，可以使用一个通用或两个。我的设备被冻结了，因为在第一个可用的中断例程（Timer0Overflow）中，没有RX中断标志检查和清除……顺便说一下，我刚才注意到上拉开关被切换为所有端口引脚（不是单个的），并且不是所有端口都有它们。嗯…- -



      以下为原文

    Ok, I'm talking to myself ;) But I'm one step further. New, shiny day has come and on my DSO waveforms appeared on TX line. Because by default I use AND masks I have missed some parameters in baud1UART() so waveforms were inverted but after quick tweaking it's OK now and I get 'a' every second.
Where things like description of "void interrupt SerialRxPinInterrupt()" can be found? It was in mentioned earlier example code but now it doesn't seem to be called and device freezes after character receiving so I guess ISR should be called differently(?).
 
EDIT:
I have digged in datasheet and I've found that this name "void interrupt SerialRxPinInterrupt()" was misleading. I had already "void interrupt Timer0Overflow()" from another example but there are no separate ISRs in this MCU. You can have one general or two - for high and low priority interrupts. My device was freezing because in first available interrupt routine (Timer0Overflow) there was no RX interrupt flag checking and clearing...
 
BTW I have just noticed that pull-ups are switched for all port pins (not individually) and not all ports have them.. argh.. :-/
 

你好，德摩克，我们会帮你的忙。抱歉耽搁了。戴维OtnPIC18应用经理



      以下为原文

    Hello demmoc,
 
We'll get you some help. Sorry for the delay.
 
David Otten
PIC18 Applications Manager

我觉得你已经解决了很多问题，如果不是全部的话。你还需要帮助吗？顺便说一下，RXIF和TXIF标志是只读的。当RX输入缓冲器中有未读数据时，RXIF标志被设置。当缓冲区为空时，读取RXREG将清除RXIF标志。当TXREG可以接受字符进行传输时，设置TXIF标志。TXIF只有在输出移位寄存器正忙于处理一个字符并且TXREG中正在挂起另一个用于传输的字符时才是清晰的。只有当发送的字符没有被写入TXRG时，才启用TX中断。当没有更多的数据要发送时禁用TXEY。



      以下为原文

   
demmoc: I appears that you have figured out many, if not all, your issues. Do you still need help? By the way, the RXIF and TXIF flags are read-only. The RXIF flag is set when there is unread data in the RX input buffer. Reading the RXREG will clear the RXIF flag when the buffer is empty.
 
The TXIF flag is set when the TXREG can accept a character for transmission. TXIF is only clear when the output shift register is busy with a character and another character for transmission is pending in the TXREG. TX interrupts should only be enabled when characters to be sent have not been written to the TXREG. Disable TXIE when no more data remains to be sent.