外部EEPROM中读取数据的问题

你好，我用PIC18F26J50作为我的控制器。



      以下为原文

    HI,
i am using PIC18F26J50 as my controller.
 
 
regards

嗯，展示你的代码…



      以下为原文

    Hmm, show your code...

代码标签，YEP，不削减第一



      以下为原文

    code tags, yep, without slash the first

CorrectThis是垃圾。不完全正确。每一个写作都必须从起始地址开始。你可以在每次转换中发送超过1个字节，只要要写入的地址的底部7位不会改变。这就是说，如果你在EEPROM地址中使用所有七个零位（即在128的倍数）开始，那么你可以写一个完整的128字节。如果你总是写四个字节，而起始地址总是四的倍数，那么你就永远不会在写中跨越一个128字节的边界，所以它是W。一次写入128个字节比一次写入4个字节更有效率。编写代码看起来过于复杂。一次写入四个字节有什么意义？每个调用EEPROMYDATA（）的读数是多少字节？将128字节的数据累积到一个数组中是非常有效的，一次写入128个，而不是一次只写四个。我也看不到其他所有“页面”代码的要点。这丝毫帮不上你的忙。



      以下为原文

   
Correct
 

This is rubbish.
 

Not totally correct.
Every write must start with the start address. You can send more than 1 byte in each transation, so long as the bottom 7 bits of the address to be written does not change. That means if you start at an EEPROM address with all seven lower bits of zero (i.e. at a multiple of 128), then you can write a full 128 bytes.
If you always write four bytes, and the start address is always a multiple of four, then you will never cross a 128 byte boundary within the write, so it will work fine.
Writing 128 bytes at a time is more efficient than writing 4 bytes at a time.
 
 
Your write code appears horribly overcomplicated. What is the point of writing four bytes at a time?
Is that how many bytes are read by each call to eeprom_data()?


 
It would be a lot more efficient to accumulate 128 bytes of data into an array, and write all 128 in one go, rather than just four at a time.
I also can't see the point of all the rest of your "page" code. It's not helping you in the slightest.
 

我的意思是，还有，垃圾的东西…



      以下为原文

   


I meant that, yep
Also, the rubbish thing...