写入C中的DSGPR0和DSGPR1

我的数据表（PIC24F）指出，为了成功地完成操作，必须连续两次写到DSGPR0。该页有一个程序集示例，但当我在代码中运行内联程序集时，这就是结果。我认为“mov.w0,w0”行把我搞得一团糟，但我不知道如何摆脱它（这个语句存在似乎有点浪费，不是吗？）我确信我遗漏了一些基本的东西，但是我没有打算成为在线组装的主人。我遗漏了什么吗？C是怎么做的？谢谢！编辑：我摆脱了扩展的内联程序集，它看起来是固定的（见下文），但是即使这个代码也不能成功地写入DSGPR1。有没有我丢失的解锁？



      以下为原文

    My datasheet (PIC24F) states that one must write to DSGPR0 twice in a row in order to successfully complete the operation.
The page has an assembly example, but when I run inline-assembly in my code, this is the result. I think the "mov.w w0, w0" line is messing me up, but I don't know how to get rid of it (seems a bit wasteful for that statement to exist any, no?)


asm volatile("MOV.w w0, %0" : "=a" (DSGPR1));
63f6: 00 00 78 mov.w w0, w0
63f8: a0 08 88 mov.w w0, 0x114
asm volatile("MOV.w w0, %0" : "=a" (DSGPR1));
63fa: 00 00 78 mov.w w0, w0
63fc: a0 08 88 mov.w w0, 0x114
I am sure that I am missing something basic, but I have no plans to be a master at inline assembly.
Is there something that I am missing? How do I do this in C?
Thanks!

EDIT:
I got rid of the extended inline assembly, and it looked fixed (seen below), but even this code does not successfully write to the DSGPR1. Is there an unlock that I am missing?


    asm volatile("MOV.w w0, _DSGPR1");
    2c86: a0 08 88 mov.w w0, 0x114
    asm volatile("MOV.w w0, _DSGPR1");
    2c88: a0 08 88 mov.w w0, 0x114