BASYS 2怎么使用USB示波器进行电源测量

取决于分流器的位置，无论如何，电力线的过滤非常显着。
调节器和接收器之间有一系列R-C组件。
您的分流器可能靠近调节器。
因此，对于25 MHz带宽范围（以及大约100 MHz的采样率？），您最可能没问题？
- 如果提供的信息有用，请将答案标记为“接受为解决方案”。给予您认为有用且回复的帖子。



以下为原文

depending on where the shunt is the power line is being filtered quite significantly anyway. There are a series of R-C components between the regulator and the sink. Your shunt is probably near the regulator. So you are most probably OK with a 25 MHz bandwidth scope (and around 100 MHz sampling rate?)- Please mark the Answer as "Accept as solution" if information provided is helpful.
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我正在使用LM2596稳压器，这正是我想知道的，如果我的25MHz带宽范围可以在100 MHz或50 MHz或25 MHz BASYS2工作频率下得到正确的测量结果，因为我们知道Nyquist-Shannon定理说
你需要至少两倍的采样频率来采取正确的样本，以避免混淆问题，但调节器可能比BASYS 2工作在更低的频率。
在本视频中，您可以看到我如何通过调节器对分流电阻器进行电压测量，您可以注意到我的系统（分流器，电路板和调节器）是如何测量的，以及示波器的参考范围如何。
我如何证明使用BW = 25MHz的这个范围，或许可以更好地使用DCM来降低BASYS2的工作频率并确保正确的测量！这对我来说是灾难性的但请告诉我25MHz带宽是否可以
接受正确的测量，真的非常感谢！
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以下为原文

I'm using the LM2596 regulator,  that is exactly what I want to know if my 25MHz bandwidth scope could get correct measurements at 100 MHz or 50 MHz  or 25MHz BASYS2 working frecuencies, c'ause as we know the Nyquist-Shannon theorem say that you need at least the double of sampling frecuency to take correct samples an avoid the Aliasing problem, but the regulator maybe work at lower frecuency than the BASYS 2.
In this video you can see how I'm taking voltage measurements over the shunt resistor in serie with the regulator , you can notice how is my system (The shunt, the board, and the regulator)  and how is the scope earth referenced as well.
How can I justify the use of this scope with BW= 25MHz, maybe it could be better to use the DCM to decrease the BASYS2 working frecuencies  and asure the correct measurements!, that would be catastrophic for me but please let me know if 25MHz bandwith could be enoung to take correct measurements, really thanks! . .
 
 

LM2596SIMPLESWITCHER®电源转换器150-kHz 3-A降压稳压器，稳压器特性可以说是150KHz，它可能是稳压器的最大工作频率，我在数据表中也发现了这个问题：
这意味着调节器不能在大于150 KHz的频率下工作！我是对的??????????
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以下为原文

LM2596 SIMPLE SWITCHER® Power Converter 150-kHz 3-A Step-Down Voltage Regulator <== the regulator caracteristic say something about 150KHz, it could be the maximun working frecuency for the regulator, I also found in the datasheet this grafic:
 

that means the regulator can't work under frequencies greater than 150 KHz!, am I right??????????¡! . .
 
 

你有两个问题：监管机构的行为和接收器的行为。
由于调节器，您将获得150 KHz的噪声及其倍数，但实际电流波形将根据负载而变化。
您要观察的行为是处理器的行为，而不是调节器的行为。
如果处理器以100 MHz的频率运行，你可能会错过一些循环来循环电流吸收器的行为，但正如我所提到的，除非你无论如何探测芯片引脚，否则你将无法测量它。
- 如果提供的信息有用，请将答案标记为“接受为解决方案”。给予您认为有用且回复的帖子。



以下为原文

you have two issues: the behavior of the regulator and the behavior of your sink. Because of the regulator you will have noise at 150 KHz and its multiples but the actual current waveform will change based on the load. The behavior you want to observe is the behavior of the processor, not that of the regulator. If the processor is running at 100 MHz, it's possible you will miss some of the cycle to cycle current sink behavior but as I have mentioned you won't be able to measure that unless you probe at the chip pins anyway.- Please mark the Answer as "Accept as solution" if information provided is helpful.
Give Kudos to a post which you think is helpful and reply oriented.

正如您在视频中所注意到的那样，示波器探头位于带调节器的串联电阻上，我需要对（电源 - 稳压器）电压的变化采取措施，我的任务与任何引脚无关。
BASYS2除了电池连接器引脚：
当然，分流电阻器与负极电池连接器引脚串联。尽管如此我接受了你的答案作为解决方案如果你发现我的论点有问题请告诉我！
因为我需要在大约2周内完成我的整个任务，谢谢！
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以下为原文

As you can notice at the video the scope probe is on the shunt resistor in serie with the regulator, I need to take measures about the variations in the (Power supply-regulator) voltage, my task has nothing to do with any pin in the BASYS2 apart from the battery conector pins:
 

Of course the shunt resistor is in serie with the negative battery conector pin.
In spite of that I accepted your answer as a solution if you notice something wrong in my arguments please let me know! because I need to finish my whole tasks in around 2 weeks, thanks! . .

你试图测量进入电路板的电流，这是法律规定的;-)，等于电路板的电流，所以电阻是与电源的正端串联还是与电源的负端串联。
供应没有太大区别（为此目的;通过将其放在电路板和电源的参考点之间，如果存在共享相同参考的其他块，则会稍微提高参考点，这可能会有问题）
- 如果提供的信息有用，请将答案标记为“接受为解决方案”。给予您认为有用且回复的帖子。



以下为原文

you are trying to measure the current going into the board, which is, by law ;-), equal to the current coming out of the board so whether the resistor is in series with the positive end of the supply or the negative end of the supply doesn't make much difference (for this purpose; by putting it between the board and the reference point of the supply, you are raising the reference point a little which can be problematic if there are other blocks which share the same reference)- Please mark the Answer as "Accept as solution" if information provided is helpful.
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