ADC通道混淆

嗨，我使用数据表中的示例代码来使用DMA读取4个ADC通道。代码看起来很好，我正在寻找我正在寻找的样本。问题是，它们处于错误的缓冲区。我把电压设置在引脚2-5上，这应该对应于ADC通道AN2-5。但是当我在引脚2（AN2）上加上电压时，在通道4上得到样本。与销3同上，它在通道5上出现噘嘴。接下来的两个别针什么也不做。下面是我的设置代码：我正在调试调试模式中的DMA缓冲区。这仅仅是我不理解某事的一个例子吗？例如，我假设AD1CSL中的位对应于ANX信道一一对应。所以当我说“0x00 3C”时，它会扫描通道2-5，谢谢！



      以下为原文

    Hi,
I used the example code out of the datasheet to read 4 ADC channels using DMA. The code seems to work fine and I am getting the samples I am looking for. The problem is they are in the wrong buffers. I am putting voltage on pins 2-5 which is supposed to correspond to ADC channels AN2-5. But when I put a voltage on pin 2 (AN2) I get samples on channel 4. Ditto with pin 3; it comes pout on channel 5. The next two pins do nothing. Here is my set up code:
AD1CON1bits.FORM = 0; // Data Output Format: Integer
    AD1CON1bits.SSRC = 2; // Sample Clock Source: GP Timer starts conversion
    AD1CON1bits.ASAM = 1; // ADC Sample Control: Sampling begins immediately after conversion
    AD1CON1bits.AD12B = 1; // 12-bit ADC operation
    AD1CON1bits.SIMSAM = 0; // Samples multiple channels individually in sequence
    AD1CON2bits.BUFM = 0;
    AD1CON2bits.CSCNA = 1; // Scan Input Selections for CH0+ during Sample A bit
    AD1CON2bits.CHPS = 0; // Converts CH0
    AD1CON3bits.ADRC = 0; // ADC Clock is derived from Systems Clock
    AD1CON3bits.ADCS = 63; // ADC Conversion Clock
    //AD1CHS0: A/D Input Select Register
    AD1CHS0bits.CH0SA = 0; // MUXA +ve input selection (AIN0) for CH0
    AD1CHS0bits.CH0NA = 0; // MUXA -ve input selection (Vref-) for CH0
    //AD1CHS123: A/D Input Select Register
    AD1CHS123bits.CH123SA = 0; // MUXA +ve input selection (AIN0) for CH1
    AD1CHS123bits.CH123NA = 0; // MUXA -ve input selection (Vref-) for CH1
    //AD1CSSH/AD1CSSL: A/D Input Scan Selection Register
    //AD1CSSH = 0x0000;
    AD1CSSL = 0x003C; // Scan AIN2, AIN3, AIN4, AIN5 inputs
    AD1CON1bits.ADDMABM = 0; // DMA buffers are built in scatter/gather mode
    AD1CON2bits.SMPI = 3; // 4 ADC buffers
    AD1CON4bits.DMABL = 3; // Each buffer contains 8 words
    IFS0bits.AD1IF = 0; // Clear the A/D interrupt flag bit
    IEC0bits.AD1IE = 0; // Do Not Enable A/D interrupt
    AD1CON1bits.ADON = 1; // Turn on the A/D converter
I am looking at the DMA buffers in debug mode. Is this simply a case me not understanding something? For example I assume the bits in AD1CSSL correspond to the ANx channels one-to-one. So when I say "0x003C" it scans channels 2-5.

Thanks!