N6762A模块怎么自动化测量

谢谢亲爱的迈克，我今天将在实验室试用它，我会告诉你的。
例如我们和N6700B一起使用模块N6762A。
这是我们想要为I-V特性自动化的那个。
我告诉你和你在回答后如何在家里改变程序的例子（附件）。



     以下为原文

  Thanks Dear Mike,
I will tried it at the lab today and i will lets you know. For instance we have and N6700B with the module N6762A. It is the one we want to automatise for I-V characteristic. I show you and example (attached file) of how i changed the program at home this nitgh after read your answer.

附件

• AgN6700b3 - Copie.vee27.6 KB
  

非常感谢亲爱的迈克，我尝试了我向你展示的程序并且它有效。
甚至是记录和输出文件。
尽管事实上它并没有瞬间绘制曲线，但对我们来说它可以完成这项工作。
我们想知道我们的N6762A是否可以用于器件的电容或阻抗。
因为我们还需要具有Capacitances-Voltages曲线和realpartZ-imaginarypartZ。
用于电气特性。
谢谢你们



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  Thanks so much Dear Mike i tried the program that i show you and it work. even for the record and the output file. despite the fact that it did not draw the curve instantanuosly but is ok for us that it do the job.
We wanted to know if it could be possible with our N6762A to the capacitance of a device or the impedance. because we do need also to have Capacitances-Voltages curves and realpartZ-imaginarypartZ. For electrical caracterisation.
thank you all

我认为答案就是'这取决于' - 主要取决于你的电容有多大。
你可以要求一个阶跃变化电压输出然后（比如，使用FOR CYCLE）监测电流的变化并从曲线中计算出电容。
但这并不理想，因为FOR CYCLE的时间由计算机确定，并且PC不是为那种时间设计的（它们对于短期时间不准确）......什么时间常数（C x R）是
你期待吗？



     以下为原文

  I think the answer to that is 'it depends' - mainly on how large your capacitance is.  You could ask for a step change voltage output and then ( say, using a FOR CYCLE ) monitor the change in current and work out the capacitance from the curve.  That's not ideal though, because the timing of FOR CYCLE is determined by the computer, and PCs are not designed for that sort of timing ( they are not accurate for short-term timing )...

What time constant ( C x R ) are you expecting?

对不起，亲爱的迈克，我不明白你真的不知道这次我们除了哪个。
我们想知道如何产生一个可用于阻抗和电容测量的电压。
我们有一个阻抗计，但它的损坏因此不能给出好的结果。
如果有可能它会帮助我们很多。
谢谢



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  Sorry dear Mike i do not understand you i really dont know which of this time we weed. We want to know how to generate an altenative voltage that we can use for impedance and capacitance measurement. We have an impedance meter but its damage so do not give good result know. If it is possible it will help us a lot.
thanks

您无法直接使用电源模块测量电容，因此您打算使用什么测量原理？



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  You cannot measure capacitance directly with your power supply module, so what measurement principle do you intend using?

我们想要描述métal-semiconductor jonctions。
因此，我们希望在我们的评价中评估潜在的理想因素和多巴胺浓度水平。
我们本来想绘制1 / C2 = f（V）来推导出一些参数。
我不知道是否有另一种方式来欺骗他们。
我还有另外一个问题。
我想知道我们的N6762A是否在负片中执行测量。
因为我连接了一个电阻，负部分的I-V特性是接近0的线，而在正部分则是OK。
我们测试过的二极管事件。
该程序没有给出负面部分的结果。
谢谢。编辑：jjjackson于2014年3月13日上午4:44



     以下为原文

  We want to caracterised métal-semiconductor jonctions. So we would want to evaluate the potential barierre the ideality factor and the level of concentration of dopans in our jonction. We would have wanted to draw 1/C2=f(V) to deduce some of those parameters. I dont know if there is another way to hace them.
I would have another probleme please. I want to know if our N6762A perform measurement in the negative part. Because went i connect a resistance, the I-V caracteristic in the negative part is a line close to 0 while in the positive part its ok. Event for some diode that we have tested. The program doesn't give results in the negative part.
thanks.

Edited by: jjjackson on Mar 13, 2014 4:44 AM

附件

• N6700b-CV.vee28.4 KB
  

哇，这涉及到了！
> {quote：title = jjjackson写道：} {quote}>我们本想绘制1 / C2 = f（V）来推导出一些参数。
我不明白，除非你的意思是电容是电压的函数？
或者你的意思是V = f（C，t）换句话说，测量的电压将是电容的函数和从符合电压的变化经过的时间（a）和（b）PSU是否设定为恒定电流？
为了解决您的第二个问题，您需要安装一个四象限设备的Agilent N6784A，以便探索设备的负面区域。



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  Wow this is getting involved!

> {quote:title=jjjackson wrote:}{quote}
> We would have wanted to draw 1/C2=f(V) to deduce some of those parameters.

I don't understand that, unless you really mean that the capacitance is a function of the voltage?  Or did you mean V = f(C,t) in other words the voltage measured will be a function of the capacitance and the time elapsed (a) from a change of compliance voltage and (b) the PSU is set to constant current?

To address your second question, you'll need something like the Agilent N6784A which is a 4-quadrant device to allow you to explore the negative regions of your device.

对不起亲爱的这可能是写作的问题。
我们在电容和电压之间存在关系。
它像电容的平方上的一个，与施加的电压和肖特基势垒成比例。
我们有旧的阻抗计，它给出了电压函数的电容值。
但它很老了，不再给出好的结果了。
我希望你这次能理解我。
所以感谢你的帮助，我很抱歉我的英语不太好用英语。
谢谢，谢谢！



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  sorry dear It may be a problem of writing. We have a relationship betwen the capacitance and the voltage. It like One over the square of the capacitance wich is proportional to the applied Voltage and the schottky barrier. We have and old impedance meter wich give us capacitances values in function of the voltages. but its very old and dont give good result anymore.
I hope you understand me this time.
So thanks for your help and im so sorry for my english im not so good in english.
thanks and thanks!!!

> {quote：title = jjjackson写道：} {quote}>我们在电容和电压之间有一种关系。
电容的平方上的一个与施加的电压和肖特基势垒成比例。
是的，我明白了，但我试图了解测量技术。
类似于：（1）施加功率（恒定电流，我假设）（2）测量电压上升...是吗？
或者你真的需要一个交流电源来测量电容（这是你的阻抗计最有可能使用的）吗？
不要担心你的英语 - 这很好，我能理解你:-)



     以下为原文

  > {quote:title=jjjackson wrote:}{quote}
> We have a relationship betwen the capacitance and the voltage. One over the square of the capacitance wich is proportional to the applied Voltage and the schottky barrier.

Yes I understand that but I was trying to get to the measurement technique.  Something like: (1) apply power ( at constant current, I'm assuming ) (2) measure the voltage as it rises... is that right?  Or do you really need an AC source to measure the capacitance ( which is what your impedance meter most likely uses ) ?

Don't worry about your English - it's very good and I can understand you  :-)

我们的阻抗计肯定适用于AC。
但如果有可能使电压变化，我们可以尝试测量阻抗。
但我们的N6762A可能无法实现。
所以我们可以继续使用阻抗计。
谢谢你的尊重。
它将为我们提供I-V特性，即使它只是在第一个四分之一（I，V> 0）我们暂时没有选择。
我今天要问的是N6784A的价格以及对我们这么贵的价格。
大学需要很长时间才能提供给我们。
再次感谢你



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  Our impedance meter surely work in AC. but if it could have been possible to make the voltage varie may be we could try to measure impedance. but its probabily impossible with our N6762A. So may be we would continu with our impedancemeter. So thank to your regard. It will serve us for I-V caracteristic even if its just in the first quadrand (I,V>0) we dont have choice for the moment. I ask today for the price of the N6784A and its so expensive for us. The university will take a long time to provide it to us. 
Thanks you again