关于AN1660的实现BLDC正弦PWM的问题

亲爱的各位，我正在写论文，所以我请求你们的帮助。我很少有关于AN1660源代码的查询。目前，我正在使用DSPIC33 F32 MC202实现基于正弦换向的无刷直流电机控制算法。这份文件帮助我理解了这些步骤。我的PWM FRQ是20kHz和正弦表与250个条目与最大振幅（32767至32767），产生正弦的80Hz。我的疑虑是：1）从输入的POT输入速度有HZ还是RPM单位？2）为什么频率仅增加到512？3）在选择可选择的振幅和频率方面是否存在权衡？4）（（SimuluDuxMax * SimeTabLax）/RealSHIFT移位）必须~=半字节任务。这个半任务对应于PWM分辨率吗？如果是，那么我有1000作为最大值，然后根据我的PWM分辨率，我没有得到500.5的值）偏移120被计算为0x55 55，如文件中所描述的，不能计算相对于样本值的偏移量吗？（如：在4K Spple表中，如果假设60DEG对应第六百六十六个样本），请做必要的。



      以下为原文

    Dear All,

I am working on my thesis so I request for your assistance. I have few queries relating to AN1660 source code. I am currently working with dsPIC33F32MC202 to implement control algorithm for BLDC control using sine commutation. The document helped me lot to understand the steps. My PWM freq is 20Khz and sine table with 250 entries with max amplitude (32767 to -32767) which produce sine of 80Hz. My doubts are:
1) Does the input speed from POT used as input arguments has unit of Hz or RPM?
2)Why is the frequency increased only till 512?
3)is there a trade-off in selecting sinetable amplitude and frequency?
4) ((AMPLITUDE_MAX * SineTableMAX)/ RIGHT_SHIFT) must ~= HALF_DUTY.. Is this HALF_DUTY is corresponding to PWM resolution? If YES then I have 1000 as PWMMAX value then according to my PWM resolution i am not getting the value of 500.
5)  Offset 120 is calculated as 0x5555 as described in document, couldn't it be possible to calculate the offset with respect to sample value? ( Eg: In a 4k smaples table, if suppose 60deg correspond to 666th sample).
Please do the needful.