当连接有源反馈时，如何实现两个晶体管的偏置

先生，我已将一个晶体管连接到另一个晶体管。
如何实现两个晶体管Vds = 3V和Ids = 60mA的偏置。
我使用了两个ATF54143晶体管，并在一个晶体管X2（如图所示）Vds = 3v（电压差为3伏，Ids = 60mA）下实现了偏置。
但是我无法在Vds和Ids = 60 mA时在X1晶体管（如图所示）上实现3伏电压的差异。
我按照Active_Feed_Example的例子连接了连接晶体管的有源反馈（如图所示）。
你能帮助我在两个晶体管上实现Vds = 3Volts和Ids = 60mA吗？
Activ_FeedBack_Example.jpg13.7 KB



     以下为原文

  Sir,
       I have connected the one transistor is feedback to the other. How to achieve the biasing for two transistors Vds = 3V and Ids=60mA.
I have used the two ATF54143 transistors, and achieved the biasing at one transistor X2(shown in figure) Vds=3v (potential difference of 3 volts and Ids = 60mA). But I couldn't achieve the difference of voltage  of 3 volts at X1 transistor (shown in figure) at Vds and Ids =60 mA. I have connected the active feed back of connection transistor as I followed the example of Active_Feed_Example(it is shown in the figure). Can you anybody help me to achieve the Vds=3Volts and Ids=60mA at the two transistors.   
附件

• ADS_CKT_Active_FeedBack.jpg232.1 KB
• Activ_FeedBack_Example.jpg13.7 KB