[问答]

怎么用功率计测量噪音

问答对人有帮助，内容完整，我也想知道答案 0 在频谱分析仪的应用笔记中，讨论了测量噪声时所需的2.3dB校正，以解释由于对数放大器，iIF滤波器以及我忘记的其他原因导致的正弦波与噪声的不同统计。使用带有标准二极管传感器头的功率计（如E系列）时是否存在类似问题。如果有，是否有应用说明或与频谱分析仪相同。谢谢.Chuck 以上来自于谷歌翻译以下为原文 In the app notes for spectrum analyzers there is discussion about the 2.3dB correction that is needed when measuring noise to account for the different statistics of sinusoids vs. noise due to the log amp, iIF filter, and something else which I've forgotten. Is there a similar issue when using a power meter with standard diode sensor heads, like the E series. If there is, is there an app note on that or is it the same as with spectrum analyzers. Thanks. Chuck 0
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答案对人有帮助，有参考价值 0 您可以使用E9300系列传感器测量噪音。噪声测量与数字调制RF信号（如CDMA）有很多共同之处。较新的传感器如E9300系列设计用于正确测量这些类型的信号，无需校正因子。本说明有一个很好的解释：http：//cp.literature.agilent.com/litweb ... -7150E.pdf 只要被测信号的峰值幅度保持在二极管的平方律区域内（在大约为二进制的平方律区域内），在平方律区域内工作的二极管将产生与平均功率成比例的输出。以上来自于谷歌翻译以下为原文 You should be OK measuring noise with an E9300-series sensor. a noise measurement has a lot in common with a digitally modulated RF signal (like CDMA). Newer sensors like the E9300-series were designed to measure these types of signals correctly, with no correction factor required. This note has a good explanation: http://cp.literature.agilent.com/litweb ... -7150E.pdf A diode operated in the square-law region will produce an output proportional to the average power as long as the peak amplitude of the measured signal is kept inside the square-law region of the diode (roughly <-20dBm). This is true for the E9300 since they have a design with high power and low power diode stacks, so they are always using the diodes inside the square law region. The E4412A/E4413A CW sensors do not have this provision, so the operator must use care to keep the peak power <-20dBm if you want to use make this type of measurement. A thermocouple sensor like the 8480 or N8480-series will always be OK for this measurement.

2019-5-22 08:09:26 评论举报冯琳