如何在没有使用软件的情况下清除100%分压器电压？

这是一个愚蠢的问题，因为你没有透露你正在谈论的PIC，或者PIC上的PIN。很可能你在PIN上有一个弱的上拉，或者其他函数，但是我们只能用你提供的限制信息来猜测。



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    It is a silly question because you have not revealed what PIC you are talking about, or what pin on that PIC.
Most likely you have a weak pullup enabled on that pin, or some other function, but we can only guess with the limted information you have provided.
 
 

是的，电阻器的值



      以下为原文

    Yeah, and the resistors' values

对不起，我忘记了最好的愚蠢的MESO PIC ISPIC16F1527，电阻器是82.5K和7.5K，引脚是ADCORDIALATANDOIO



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    Sorry I forgot the best silly me
 
So the pic is PIC16F1527 the resistor is 82.5k and 7.5k the pin is an ADC
 
Cordially 
Antonio 

哪一个？含糊不清的回答不会得到好的答复。



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Which one?
Vague answers won't get good replies.
 

引脚45 ADC通道ANY20



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    Pin 45 ADC channel AN_20

AN20是PIN RB3。该引脚具有弱的上拉。它是由WPUB控制的。你在那个名册上有什么价值？



      以下为原文

    AN20 is pin RB3.
That pin has a weak pullup. It is controlled by WPUB. What value do you have in that register?
 

对登记册里的价值一无所知，我怎么能看到呢？顺便说一下，我用的是皮克特谢谢。我也试过PIN：1~6，11~18.21~27，43~45，结果不改变谢谢。



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    No idea about the value in the register, how can i see it. I am using a PICkit3
 
Thank by the way. I have tried also for PIn:1to6,11to18,21to27, 43to45
 
the result does not change
 
Many thanks
 
 

所以你不是用你的安装代码写的吗？假设默认值对你来说是危险的。为什么不直接写0x00到WPUB，这样你就知道它们被禁用了？注意：数据表告诉您WPUB的默认值是0xFF，但是如果OpTythReg中的WPUN位被清除，它只会生效。您是否曾经给OpTythReg写过？



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    So you are not writing to it in your setup code?
It's dangerous to assume default values will work for you.
Why not just write 0x00 to WPUB so you know they are disabled?
 
Note: the datasheet tells you the default value of WPUB is 0xFF, but it only takes effect if the WPUEN bit in OPTION_REG is cleared.
Do you ever write to OPTION_REG?
 
 

你好，不，我没有。事实上，我最近开始使用PIC，所以我用代码配置来设置ADC引脚，然后我用标准函数读取PIN。之后，我刚刚转换了电压值。这是我编写的代码：PrtTf（n N电压通道20是：%.2fnr），ADCQGET转换（ChhanNel-An20）/ 204.16）；/通过读取GET转换函数打印引脚上的电压，并通过除以204.16d转换电压值。你介意给我一些例子来清洁它吗？或者解释如何在OpthyReg中写作？然后我会调查。非常感谢你的帮助。



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    Hello Again,
 
No i have not. Actually i recently start using PIC and so i have used code configuration to set up the ADC pin and then i have used the standard function to read the pin. After that i  have just converted the value in Voltage.
 
This is the code i have written:
printf(" n Voltage Channel 20 is: %.2f nr", ADC_GetConversion(channel_AN20)/204.16); //print the voltage on the pin by reading the get conversion function and convert the value in voltage by dividing by 204.16
 
 
Do you mind give me some example code  to clean it ? or explain how can write in Option_REG? then i will investigate.
 
Thank you so much for your help.
 
Cordially 
Antonio 
 
 

这就是代码配置器的问题。你真的不知道它写了什么。如果你想知道WPUB中的内容，你可以打印它。例如，试着在初始化代码中清除它。例如



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    That's the problem with code configurators. You don't really know what it has written to.
If you wanted to know what was in WPUB, you could just print it.
e.g. 
printf("WPUB is: %02xnr",WPUB);
Just try clearing it in your initialisation code. e.g.
WPUB = 0;
 

是的，现在起作用了，非常感谢。但另一个问题是，当引脚处于浮点，而不是电线连接，没有电压进来，它读取1.5 Vo请，如果我不要求太多。你有没有一个指南，一步一步地解释如何设置PIC，而不看数据表，对于我来说仍然是阿拉伯语的许多感恩节。



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    Yes, It works now, thank you so much. But gives another problem
 
When the pin is in floating point not wires attached, not voltage coming in, it reads 1.5V
 
Please, if i do not ask too much. do you have any guide that explains step by step how to set up the pic without see the Datasheet which for me still be Arabic 
 
Many thanks
 
Antonio

它不能浮，永远，只有规则，其余看起来不错，正如你所说的，所以…



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    It must not float, never, only rule
the rest looks ok, as you say, so...

如果您把电压分压器和滤波元件放在PIC附近，HIIT将永远不会浮起。如果开关可以断开/重新连接，则必须在开关和任何信号调节/滤波电路之间插入插头。这样，当没有开关时，分压器和FI。LITEN电路仍将在那里上下PIC引脚防止其浮动。



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    Hi
 
It will never float if you put the voltage divider and filtering components near the PIC.
If the switch can be disconnected/reconnected, the plug must be inserted between the switch and any signal conditioning/filtering circuitry.
This way when there is no switch present, the voltage divider and filtering circuitry will still be there to pull up/down the PIC pin preventing it to float.
 
Best regards
Jorge
 

谢谢你这么多



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    Thank you so much 
 
A

如果你想理解，一遍又一遍的读数据表，直到你明白。如果你不想理解，预计编程是非常困难的。



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If you want to understand, read the datasheet over and over again until you understand.
 
If you don't want to understand, expect the programming to be very hard.

大多数PIC的数据表显示了配置ADC和使用它的相当简单的步骤，但示例通常在汇编程序中。学习汇编语言的基本知识是明智的，试着用几个项目来理解最低级的情况。有时C代码隐藏某些重要的概念，MCC增加了另一个抽象级别。我发现经常需要仔细阅读生成的代码。它经常有错误、可疑的代码和低效。有时我发现数据表比MCC对话框更容易理解。此外，MCC和数据表有时不提供对外部电路考虑的完全指导。搜索教程和完整的、有良好文档的项目通常作为正确设计的硬件的例子是很有用的。Microchip为他们的PicDEM、PICkit、Explorer和好奇心评估板提供了完整的原理图，这可以作为一个起点。



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    The datasheets for most PICs show fairly simple steps for configuring the ADC and using it, but the examples are usually in assembler. It is wise to learn at least the rudiments of assembly language and try a few projects using it to understand what's going on at the lowest levels. Sometimes C code hides certain important concepts, and the MCC adds another level of abstraction. I have found that it's often necessary to read the generated code carefully. and it often has errors, questionable code, and inefficiencies. Sometimes I have found the datasheets easier to understand than the MCC dialogs.
 
Also, the MCC and sometimes the datasheet do not provide complete guidance for external circuitry considerations. It is often helpful to search for tutorials and complete, well-documented projects to use as examples of properly designed hardware. Microchip provides complete schematics for most of their PICdem, PICkit, Explorer, and Curiosity evaluation boards, which can serve as a starting point.

因为没有其他人提到它……这是一个相对高阻抗（几乎100K）的分压网络，并且……即使是弱的拉出也会影响它。我建议把电阻值缩小5-10倍，以降低电路的阻抗。即使是一个-10的减少，仍然只消耗20Ma从你的20V电源，但将大大降低你对噪音的敏感性和弱内部拉柱的影响。很久以前我默认为相当高的值在我的电阻分压器，认为我是“节约电流”和“这只是一个参考。艾伦斯不再了。如果较低值的“浪费电流”对于应用程序来说太多，则可能需要以其他方式导出参考电压（运算放大器等）。最后，由于您将节点直接驱动到A/D输入，所以一个小的并行滤波器来过滤噪声是便宜的，不会造成损害。



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    Since no one else mentioned it:

...that's a relatively high impedance (almost 100K) divider network, and:

...even a weak pullup is going to affect it. I suggest scaling down your resistor values by a factor of 5-10x to drop the impedance of the circuit. Even a factor-of-10 reduction will still only consume ~2mA from your 20V supply but will dramatically reduce your susceptibility to noise and the effects of weak internal pullups.
 
Long ago I defaulted to rather high values in my resistor dividers, thinking I was "saving current" and "it's only a reference". Not anymore. If the "wasted current" of the lower values is too much for your application, you probably need to derive that reference voltage in some other manner (op amp, etc.).
 
Finally, since you're driving the node directly into an A/D input, a small parallel cap to filter noise is cheap and wouldn't hurt.

这是一个相对高阻抗（几乎100K）的分配器网络，电阻分压器在中心节点的阻抗，是两个电阻并联的，所以在这种情况下，它是82.5K//7.5K＝69K。这就是为什么我没有对它做进一步评论的原因。



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...that's a relatively high impedance (almost 100K) divider network
 
The impedance of a resistor divider AT THE CENTRE NODE, is of the two resistors in parallel, so in this case it is 82.5k // 7.5k = 6.9k.
That's why I didn't comment further on it.
 

授予。我关注的是当前的消费，因为这促使大多数人在他们的分销商中使用高价值。~7K实际上相当高。在几乎任何应用中都被认为是非常高的阻抗。如果按所建议的系数减少10，则该节点将达到690欧姆-远不易受噪声和内部内部拉力的影响。



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    Granted. I was fixated on the current consumption since that's what prompts most people to use high values in their dividers.
 
My point still stands, though. ~7K is actually quite high. Considered a very high impedance in almost any application. If he reduces by a factor of 10 as suggested, that node will go to 690 ohms - far less susceptible to noise and the weak internal pullup.