关于5700N最小电压/电流额定值的问题

嗨Jon，N5700电源是单象限直流电源。
我们所有的电源都有编程规格的偏移误差。
比如说你使用的是N5742A。
电压编程规格为.05％+ 4 mV，电流编程规格为0.1％+ 90 mA。
这意味着在CV模式下，当电源设置为0 V时，它可能低至-4 mV。
我们偏置电源，使它们始终在正确的象限中开始（电压始终为正）。
这并不意味着当设备处于CV模式时你不能拥有0 A.
此规定仅适用于您可以编程的最小电压。
欧姆定律永远都是正确的。
在您的示例中，该单元将流过0.1 mA。
如果这对您有意义，请告诉我。



     以下为原文

  Hi Jon,

The N5700 power supplies are single quadrant DC Power supplies.  All of our power supplies have an offset error to the programming specs.  Let's say for instance you are using a N5742A.  The voltage programming spec is .05% + 4 mV and the current programming spec is 0.1% + 90 mA.  That means that in CV mode, when you have the supply set to 0 V, it could be as low as -4 mV.  We bias our power supplies so that they always start out in the correct quadrant (the voltage will always be positive).   

This does not mean that you can't have 0 A when the unit is in CV mode though.  This stipulation is only for the minimum voltage that you can program.  Ohm's law will always hold true.  In your example, the unit will have 0.1 mA flowing. 

Let me know if this makes sense to you.

谢谢马特，这回答了我的问题。
乔恩



     以下为原文

  Thanks Matt, that answers my question.

Jon