在屏幕已满之前强制重新触发

在采集存储器和/或显示器已满之前，您无法强制重新触发。
但是，您可以更改触发机制。
这听起来好像使用了脉冲宽度触发器。
你没有说出这个信号的正常状态是低还是高。
假设它通常很低，并且每1次使用它应该高达100nsec，那么我会使用脉冲宽度触发器来寻找比1usec更宽的负脉冲（信号下降，然后向上）。
这些值，也许极性会根据您的需求而改变，但这应该有所帮助。
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     以下为原文

  You can't force a retrigger before the acquisition memory and/or display is full. You can however, change your triggering mechanism.

This sounds like a good use of the pulse width trigger. You don't say what the normal state of this signal is, low or high. Assuming it's normally low, and it should go high  for 100nsec every 1 usec, then I would use a pulse width trigger that looks for a negative pulse (signal going down, then up) that is wider than 1usec. These values, and maybe the polarity will change, based on your needs, but this should help.

Al

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谢谢你的回答，虽然这不是我所希望的。
触发信号以50％的占空比上下移动，周期在1.6到4秒之间变化。
发生错误后信号保持不变。
我想过使用脉冲宽度触发器，问题是触发事件需要额外的边缘。
信号长时间保持不变，但这个“太长”的时间需要结束以触发触发。
在我的情况下，信号永远不会再次回落。
我自己可以创建这个额外的边缘，但到那时，失败时发生的事情的记忆早已不复存在。
我误会了吗？



     以下为原文

  Thanks for the answer, although it was not what I was hoping for.

The trigger signal goes up and down with 50 % duty cycle, and periods varying between 1.6 and 4 seconds. The signal stays up after the error has occurred.
I thought about using the pulse width trigger, the problem is that an additional edge is needed for the trigger event. The signal stays up for too long, but this "too long" time needs to end for the trigger to fire. In my case, the signal does never get back down again. I could create this additional edge myself, but by then the memory of what happen at the failure time is long gone.

Did I misunderstand?

然后在大于4秒的正脉冲宽度上触发。
示波器将寻找上升沿，当它看到它时，它将在4秒内寻找下降沿。
如果它没有看到，它将触发。
如果它看到下降沿，它将寻找下一个上升沿并从头开始。
这可能需要一些实验。
如果示波器无法做到，则将LED连接到电路并设置外部触发按钮。
当LED看起来太长时按下按钮。
这一切都足够慢，你的眼手协调可能会接管。
人



     以下为原文

  Then trigger on a positive pulse width greater than 4 seconds. The scope will be looking for a rising edge, when it sees it, it will look for a falling edge within 4 seconds. If it doesn't see one, it will trigger. If it sees a falling edge, it will look for the next rising edge and start all over.

This may take some experimentation. If the scope can't do it, then connect an LED to the circuit and set up an external trigger for when you push a button. Push the button when it looks like the LED has been on too long. This is all slow enough that your eye-hand coordination may be able to take over.

Al

algoss：>如果没有看到，它会触发。
这在我的MSO6012A上似乎不正确。
它需要以下的优势。
algoss：>这一切都足够慢，你的眼手协调可能会接管。
如果我很幸运，在错误发生之前可能需要12个小时的压力测试。
我很可能会错过它。
Thomas001：好的第一篇文章，你明白了！
在我的MSO6012A上，它处于触发器More-> Duration。
当我发布我的问题时，我必须说我不是很乐观，所以这是一个很好的惊喜。
谢谢你们俩！
编辑：gauthier于2013年4月24日12:25 AM编辑：gauthier于2013年4月24日12:58 AM



     以下为原文

  algoss:
> If it doesn't see one, it will trigger.

This does not seem to be correct on my MSO6012A. It needs the following falling edge.

algoss:
> This is all slow enough that your eye-hand coordination may be able to take over.

It could take 12 hours of stress testing before the error occurs, if I am lucky. I am very likely to miss it.

Thomas001:
Nice first post, you got it! On my MSO6012A it is in the trigger More->Duration. I must say I wasn't very optimistic when I posted my question, so this is a nice surprise.

Thank you both!

Edited by: gauthier on Apr 24, 2013 12:25 AM

Edited by: gauthier on Apr 24, 2013 12:58 AM

使用触发类型“Pattern”并将Channel设置为“1”或“0”，所有其他通道应设置为“X”。
将限定符设置为“超时”并将时间调整为4或5秒。
缺少信号将导致触发。



     以下为原文

  Use trigger type "Pattern" and set Channel to either  "1" or "0" and all other channels should be set to "X".  The set the Qualifier to "Timeout" and adjust the time to 4 or 5 seconds.  The lack of a signal will cause a trigger.