[问答]

E5071C的比例误差不明白

1132 E5071C

问答对人有帮助，内容完整，我也想知道答案 0 嗨，我正坐在并试图了解校准证书中的AUX输入测试。该测试包含两个部分，偏移误差和比例误差。第一部分关闭测试偏移误差我理解但比例错误我不明白。在服务手册中，边界为-0.01≤比例误差≤+ 0.01.01直流电压±1V，±10V，在测量报告上，边界为±11mV，任何人都可以向我描述测量结果。以上来自于谷歌翻译以下为原文 Hi I´m sitting and trying to understand AUX input test in the calibration certificate. The test contains off two parts, offset error and proportional error. the first part off the test with the offset error i understand but proportional error i don´t get it. In the service manual the boarder is -0.01 ≤ Proportional Error ≤ +0.01 @ DC voltage ±1V, ±10V and on the measurement report the boarder is ±11mV can anyone describe the measurment to me. 0
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答案对人有帮助，有参考价值 0 > {quote：title = kuggkrans写道：} {quote}>我好，我正在试图了解校准证书中的AUX输入测试。该测试包含两个部分，偏移误差和比例误差。第一部分关闭测试偏移误差我理解但比例错误我不明白。在服务手册中，边界>>-0.01≤比例误差≤+ 0.01.01直流电压±1V，±10V >>，在测量报告中，边界为±11mV>>任何人都可以向我描述测量结果。我不为安捷伦工作，也不了解仪器，但你的问题让我看了。根据http://cp.literature.agilent.com/litweb/pdf/5989-5479EN.pdf，有两个输入范围，+ / - 1V和+/- 10 V.前者的规格为1％ + 1 mV，后者为1％+ 10 mV。所以我假设在+/- 1V范围内最大误差为0.01 * 1 + 0.001 = 0.011 V = 11 mV，在+/- 10 V范围内，它将是10 * 0.01 + 0.01 = 0.11 V = 110 毫伏。因此，+ / - 1 V范围内的最大允许误差为11 mV，这是您的校准证书所显示的。这是某种低频输入，您可以使用VNA中的A到D进行测量吗？如果是这样，我假设一个直流电压施加到BNC输入，并在VNA上测量它。错误不应超过规范中的错误。许多仪器都有一些辅助输入和输出连接器，这些连接器有时很方便，但不是仪器的主要用途。我怀疑这就是你在这里所拥有的。编辑：drkirkby于2013年9月11日上午10:54编辑：drkirkby于2013年9月11日上午10:57 以上来自于谷歌翻译以下为原文 > {quote:title=kuggkrans wrote:}{quote} > Hi I´m sitting and trying to understand AUX input test in the calibration certificate. The test contains off two parts, offset error and proportional error. the first part off the test with the offset error i understand but proportional error i don´t get it. In the service manual the boarder is > > -0.01 ≤ Proportional Error ≤ +0.01 @ DC voltage ±1V, ±10V > > and on the measurement report the boarder is ±11mV > > can anyone describe the measurment to me. I don't work for Agilent, and don't know the instrument, but your question got me looking. According to http://cp.literature.agilent.com/litweb/pdf/5989-5479EN.pdf there are two input ranges, which are +/- 1V and +/- 10 V. The spec for the former is 1% + 1 mV and the for latter is 1% + 10 mV. So I would assume on the +/- 1V range the maximum error is 0.011+0.001 = 0.011 V = 11 mV, and on the +/- 10 V range, it would be 100.01+0.01 = 0.11 V = 110 mV. Hence the maximum permissable error on the +/- 1 V range would be 11 mV, which is what your cal certificate is showing. Is this some sort of low frequency input which you can measure with an A to D in the VNA? If so, I assume one applies a DC voltage to the BNC input, and measures it on the VNA. The error should not exceed that in the specs. Many instruments have some auxiliary input and output connectors, which are sometimes handy, but are not the main purpose of the instrument. I suspect this is what you have here. Edited by: drkirkby on Sep 11, 2013 10:54 AM Edited by: drkirkby on Sep 11, 2013 10:57 AM

2018-12-13 17:15:59 评论举报李青