关于28335的ECAP模块

我使用28335的ECAP1通道采集 一个1M的信号，4个捕获寄存器里面的值如下：
    t1= ECap1Regs.CAP1;
    t2= ECap1Regs.CAP2;
    t3= ECap1Regs.CAP3;
    t4= ECap1Regs.CAP4;
按照我的理解，应该t1 再者，我希望捕获到所有的高低沿变化，采用这种方式，是否会有遗漏或隐患？？？
ECAP1的初始化代码如下：
void SetCap1Mode(void)
{
  ECap1Regs.ECCTL1.bit.CAP1POL = EC_RISING;
  ECap1Regs.ECCTL1.bit.CAP2POL = EC_FALLING;
  ECap1Regs.ECCTL1.bit.CAP3POL = EC_RISING;
  ECap1Regs.ECCTL1.bit.CAP4POL = EC_FALLING;
  ECap1Regs.ECCTL1.bit.CTRRST1 = EC_ABS_MODE;
  ECap1Regs.ECCTL1.bit.CTRRST2 = EC_ABS_MODE;
  ECap1Regs.ECCTL1.bit.CTRRST3 = EC_ABS_MODE;
  ECap1Regs.ECCTL1.bit.CTRRST4 = EC_ABS_MODE;
  ECap1Regs.ECCTL1.bit.CAPLDEN = EC_ENABLE;
  ECap1Regs.ECCTL1.bit.PRESCALE = EC_DIV1;
  ECap1Regs.ECCTL2.bit.CAP_APWM = EC_CAP_MODE;
  ECap1Regs.ECCTL2.bit.CONT_ONESHT = EC_CONtiNUOUS;
  ECap1Regs.ECCTL2.bit.SYNCO_SEL = EC_SYNCO_DIS;
  ECap1Regs.ECCTL2.bit.SYNCI_EN = EC_DISABLE;
  ECap1Regs.ECEINT.all=0x0000;//stop all interrupt
  ECap1Regs.ECCLR.all=0xFFFF;//clare all flag
  ECap1Regs.ECCTL2.bit.TSCTRSTOP = EC_RUN;// 启动
  ECap1Regs.ECEINT.bit.CEVT4=1;// Enable cevt4 interrupt
}