[讨论]

电子密码锁设计

2014-12-29 21:18:27 2867 密码锁

0 #include #define KEY_Prot P3 unsigned char Pre_KeyNO,i = 0,flag = 0; unsigned char code duan_tab[]={0xC0,0xF9,0xA4,0xB0,0x99, 0x92,0x82,0xF8,0x80,0x90,0xBF}; unsigned char code wei_tab[]={0xFE,0XFD,0XFB,0XF7,0XEF,0XDF,0XBF,0X7F}; #define Wei P0 #define Duan P1 unsigned char mima[]={1,1,1,1,1,1}; void delay_ms(unsigned int ms) { unsigned int i,j; for(i = 0;i<80;i++) for(j = 0;j } void led_show(unsigned char a,unsigned char b,unsigned char c) { unsigned char i; unsigned char date[8]; date[0] = a/10; date[1] = a%10; date[2] = 10; date[3] = b/10; date[4] = b%10; date[5] = 10; date[6] = c/10; date[7] = c%10; for(i = 0 ;i < 8;i++) { Wei = wei_tab[i]; Duan = duan_tab[date[i]]; delay_ms(1); } } unsigned char Keys_Scan() { unsigned char Tmp,KeyNO = 0; KEY_Prot = 0x0f; delay_ms(1); Tmp = KEY_Prot ^ 0x0f; switch(Tmp) { case 1: KeyNO = 0; break; case 2: KeyNO = 1; break; case 4: KeyNO = 2; break; case 8: KeyNO = 3; break; default: KeyNO = 16; } KEY_Prot = 0xf0; delay_ms(1); Tmp = KEY_Prot >> 4 ^ 0x0f; switch(Tmp) { case 1: KeyNO += 0; break; case 2: KeyNO += 4; break; case 4: KeyNO += 8; break; case 8: KeyNO += 12; } return KeyNO ; } void main() { TMOD = 0X01; TH0 = (65535 - 10000)/256; TL0 = (65535 - 10000)%256; ET0 = 1; TR0 = 1; EA = 1; while(1) { P3 = 0xf0; //初始化按键状态 if(P3 != 0xf0)//按键按下判断 { flag++; Pre_KeyNO = Keys_Scan();//返回按键键值 while(!(P3 == 0xf0)); //扫描抬键判断 if(Pre_KeyNO>=0&&Pre_KeyNO<=9)//有效数据判断 { if(Pre_KeyNO ==mima[i] )//数据匹配 { i++; //如果正确，i++匹配下一位数据 }else { i = 0;//不正确返回初始化状态 } } if(i == 6&&Pre_KeyNO == 10)//确认键按下时 { P2 =~P2; i = 0; } } } } void timer_0()interrupt 1 { TH0 = (65535 - 20000)/256; TL0 = (65535 - 20000)%256; led_show(0,i,Pre_KeyNO); } 为什么我设置密码是6个1的，但是通过按键只能显示3个1而已，这是为什么啊？请各位大神指导。 0
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