字节数组怎么转换为int16s数组

>数据首先显示为LSB>而To / From Socket对象>首先假设它是MSB。我的！
好吧，是的，我可以想到一个更快的方法，但我认为更大的问题是，无论发送数据是什么都不正确！
网络字节顺序发布为对应用程序层透明。
IOW，htons（）首先没有使用。基本上，只需将字节移动到一个Int16数组中。
如果没有其他解决方案在同一时间呈现，我会详细说明当我从今天的小方向回来。-SHAWN ----您目前订阅vrf为：r***@soco.agilent.com要订阅发送空白电子邮件至“
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     以下为原文

  > the data is presented as LSB first
> whereas the To/From Socket object
> assumes it's MSB first.

Oh my! Well, yes I can think of a faster way but I think the larger problem
is that whatever is sending the data is incorrect! Network byte order is
supposed to be transparent to the application layer. IOW, htons() was not
used in the first place.

Basically, just move the bytes into an Int16 array en masse. I'll elaborate
when I get back from today's little side track if no other solution presents
itself in the mean time.
-SHAWN-



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我不知道你是否必须处理负数，但如果你这样做，我认为该公式会导致int16的整数溢出，或者不会将预期的2的补码作为int32 .-- Bill OssmannPhilips Ultrasounde-mail：bill。
ossmann@philips.comGraeme希尔顿写于11/02/2005 10:00:12 AM：>谢谢Dave，>>我不得不捏一点让这个接受我的数据，但它仍然有效。>>但是，我坚持了下来
再看一下套接字读数，然后来了：>>来自Socket，READ BINARY x BYTE ARRAY：16001,2>然后一个公式：（x [*，1] * 256 + x [*，0]）
结合两个>字节的列。>>非常快速和简单。>> - > Graeme Hilton> R＆amp; D工程师>> Schlumberger Sensa >>> David Watling在02/11/2005 14上写了以下内容：
08：>>你好Graeme，>>我写了一个byteswop公式，它可以在>>一次对数组的所有元素起作用。
将数组加载为INT16，然后运行swopper功能。
您可能>>或者也可能不想要2的cmpl函数。> >>>函数byteswop int16：>> bitOr（bitAnd（bitShift（A，-8），＃H00ff），bitAnd（bitShift（A，8），
＃Hff00））;> >>> 2的cmpl >> asInt16（A-（A DIV 32768）* 65536）;> >> >>>问候> >>> David Watling> >>> -----原始信息
----->>来自：Graeme Hilton [mailto：GHilton@slb.com]>>发送时间：2005年11月2日13:43 >> To：VRF >>主题：[vrf]字节数组转换为int16s数组
> >>>大家好，> >>>这是我最新的谜题;> >>>我正在从TCP / IP套接字读取数据。
我读取32002个字节，>>代表>> 16001 16位整数。
我不能使用READ BINARY x INT16 ARRAY1D >> 16001，因为>>数据首先显示为LSB，而To / From Socket对象通常>>它的>> MSB优先。> >>>将这些数字拼接在一起我运行
通过以下内容：>> For Each（A [2 * i] + A [（2 * i）+1] * 256）并收集结果以创建我的>> int16 >> 16001元素数组。> >>>
我的问题是这需要花费大量的时间（相比于>>其余的>程序）。
有没有人有一个非循环的方式这样做或>>另一个>节省时间的方法？> >>> --->您目前订阅vrf为：bill.ossmann@philips.com>订阅发送一个
空白电子邮件至“join-vrf@it.lists.it.agilent.com”。>要取消订阅，请发送空白电子邮件至“leave-vrf@it.lists.it.agilent.com”。>发送邮件至此邮件
列表，请发送电子邮件至“vrf@agilent.com”。>如果您需要有关邮件列表的帮助，请发送邮件至“owner-> vrf@it.lists.it.agilent.com”。>搜索“非官方vrf档案”，
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     以下为原文

  I don't know if you have to deal with negative numbers, but if you do I
think that formula will cause an integer overflow for an int16, or not give
the expected 2's complement as an int32.
--
Bill Ossmann
Philips Ultrasound
e-mail:  bill.ossmann@philips.com

Graeme Hilton wrote on 11/02/2005 10:00:12 AM:

> Thanks Dave,
>
> I had to fiddle a little to get this to accept my data, but it works
well.
>
> However, I persevered a little more with the socket reading and came
> up with this:
>
>  From Socket, READ BINARY x BYTE ARRAY:16001,2
> Then a formula: (x[*,1]*256+x[*,0]) to marry the two columns of
> bytes together.
>
> Very quick and very simple.
>
> --
> Graeme Hilton
> R&D Engineer
>
> Schlumberger Sensa
>
>
> David Watling wrote the following on 02/11/2005 14:08:
> > Hi Graeme,
> > I wrote a byteswop formula which works on all elements of the array at
> > once.  Load the array as INT16, then run the swopper function.  You may
> > or may not want the 2's cmpl function as well.
> >
> > Function byteswop int16:
> > bitOr(bitAnd(bitShift(A,-8),#H00ff),bitAnd(bitShift(A,8),#Hff00));
> >
> > 2's cmpl
> > asInt16(A-(A DIV 32768)*65536);
> >
> >
> > Regards
> >
> > David Watling
> >
> > -----Original Message-----
> > From: Graeme Hilton [mailto:GHilton@slb.com]
> > Sent: 02 November 2005 13:43
> > To: VRF
> > Subject: [vrf] Array of bytes convert to array of int16s
> >
> > Hi All,
> >
> > Here's my latest puzzle;
> >
> > I am reading data from a TCP/IP socket.  I read 32002 bytes which
> > represent
> > 16001 16-bit integers.  I can't use the READ BINARY x INT16 ARRAY1D
> > 16001 as the
> > data is presented as LSB first whereas the To/From Socket object
assumes
> > it's
> > MSB first.
> >
> > To stitch these numbers together I run through the following:
> > For Each (A[2*i]+A[(2*i)+1]*256) and collect the results to create my
> > int16
> > array of 16001 elements.
> >
> > My problem is that this takes a significant amount of time (compared to
> > the rest
> >   of the program).  Does anyone have a non-looping way of doing this or
> > another
> > time-saving method?
> >
>
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大家好，这是我最新的谜题;我正在从TCP / IP套接字读取数据。
我读取32002个字节，代表16001个16位整数。
我不能使用READ BINARY x INT16 ARRAY1D 16001，因为数据首先显示为LSB而To / From Socket对象假定它是MSB优先。要将这些数字拼接在一起，我将执行以下操作：For Each（A [2 *
i] + A [（2 * i）+1] * 256）并收集结果以创建我的1616个元素的int16数组。我的问题是这需要花费大量时间（与程序的其余部分相比）。
有没有人采用非循环方式做到这一点或另一种节省时间的方法？ - Graeme HiltonR＆amp; D EngineerSchlumberger Sensa ---您目前订阅了vrf：r***@soco.agilent.com要订阅，请发送空白电子邮件至
“join-vrf@it.lists.it.agilent.com”。要取消订阅，请发送一封空白电子邮件至“leave-vrf@it.lists.it.agilent.com”。要向此邮件列表发送邮件，请发送电子邮件至“vrf”
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     以下为原文

  Hi All,

Here's my latest puzzle;

I am reading data from a TCP/IP socket.  I read 32002 bytes which represent
16001 16-bit integers.  I can't use the READ BINARY x INT16 ARRAY1D 16001 as the
data is presented as LSB first whereas the To/From Socket object assumes it's
MSB first.

To stitch these numbers together I run through the following:
For Each (A[2*i]+A[(2*i)+1]*256) and collect the results to create my int16
array of 16001 elements.

My problem is that this takes a significant amount of time (compared to the rest
  of the program).  Does anyone have a non-looping way of doing this or another
time-saving method?

--
Graeme Hilton
R&D Engineer

Schlumberger Sensa

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大家好，这是我最新的谜题;我正在从TCP / IP套接字读取数据。
我读取32002个字节，代表16001个16位整数。
我不能使用READ BINARY x INT16 ARRAY1D 16001，因为数据首先显示为LSB而To / From Socket对象假定它是MSB优先。要将这些数字拼接在一起，我将执行以下操作：For Each（A [2 *
i] + A [（2 * i）+1] * 256）并收集结果以创建我的1616个元素的int16数组。我的问题是这需要花费大量时间（与程序的其余部分相比）。
有没有人采用非循环方式做到这一点或另一种节省时间的方法？ - Graeme HiltonR＆amp; D EngineerSchlumberger Sensa ---您目前订阅了vrf：r***@soco.agilent.com要订阅，请发送空白电子邮件至
“join-vrf@it.lists.it.agilent.com”。要取消订阅，请发送一封空白电子邮件至“leave-vrf@it.lists.it.agilent.com”。要向此邮件列表发送邮件，请发送电子邮件至“vrf”
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     以下为原文

  Hi All,

Here's my latest puzzle;

I am reading data from a TCP/IP socket.  I read 32002 bytes which represent
16001 16-bit integers.  I can't use the READ BINARY x INT16 ARRAY1D 16001 as the
data is presented as LSB first whereas the To/From Socket object assumes it's
MSB first.

To stitch these numbers together I run through the following:
For Each (A[2*i]+A[(2*i)+1]*256) and collect the results to create my int16
array of 16001 elements.

My problem is that this takes a significant amount of time (compared to the rest
  of the program).  Does anyone have a non-looping way of doing this or another
time-saving method?

--
Graeme Hilton
R&D Engineer

Schlumberger Sensa

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嗨Graeme，我写了一个byteswop公式，它适用于数组atonce的所有元素。
将数组加载为INT16，然后运行swopper功能。
你可能也不想要2的cmpl函数。函数byteswop int16：bitOr（bitAnd（bitShift（A，-8），＃H00ff），bitAnd（bitShift（A，8），＃Hff00））; 2的cmplasInt16（A
- （A DIV 32768）* 65536）; RegardsDavid Watling -----原始信息-----来自：Graeme Hilton [mailto：GHilton@slb.com]发送时间：2005年11月2日13:43T：VRFSubject：[vrf
]字节数组转换为int16sHi数组全部，这是我最新的谜题;我正在从TCP / IP套接字读取数据。
我读取32002个字节，代表16001个16位整数。
我不能使用READ BINARY x INT16 ARRAY1D16001，因为数据首先显示为LSB而To / From Socket对象首先假设MSB。要将这些数字拼接在一起，我将执行以下操作：For Each（A [2 * i]
+ A [（2 * i）+1] * 256）并收集结果以创建16001个元素的myint16数组。我的问题是这需要花费大量时间（与程序的其余部分相比）。
有没有人采用非循环的方式来实现这种省时省力的方法？ - Graeme HiltonR＆amp; D EngineerSchlumberger Sensa ---您目前订阅了vrf：watling@icerasemi.com要订阅，请发送空白电子邮件至“加入 -
vrf@it.lists.it.agilent.com“。要取消订阅，请发送一封空白电子邮件至”leave-vrf@it.lists.it.agilent.com“。要发送邮件到此邮件列表，请发送电子邮件至”vrf @ agilent。
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     以下为原文

  Hi Graeme,
I wrote a byteswop formula which works on all elements of the array at
once.  Load the array as INT16, then run the swopper function.  You may
or may not want the 2's cmpl function as well.

Function byteswop int16:
bitOr(bitAnd(bitShift(A,-8),#H00ff),bitAnd(bitShift(A,8),#Hff00));

2's cmpl
asInt16(A-(A DIV 32768)*65536);


Regards

David Watling

-----Original Message-----
From: Graeme Hilton [mailto:GHilton@slb.com]
Sent: 02 November 2005 13:43
To: VRF
Subject: [vrf] Array of bytes convert to array of int16s

Hi All,

Here's my latest puzzle;

I am reading data from a TCP/IP socket.  I read 32002 bytes which
represent
16001 16-bit integers.  I can't use the READ BINARY x INT16 ARRAY1D
16001 as the
data is presented as LSB first whereas the To/From Socket object assumes
it's
MSB first.

To stitch these numbers together I run through the following:
For Each (A[2*i]+A[(2*i)+1]*256) and collect the results to create my
int16
array of 16001 elements.

My problem is that this takes a significant amount of time (compared to
the rest
  of the program).  Does anyone have a non-looping way of doing this or
another
time-saving method?

--
Graeme Hilton
R&D Engineer

Schlumberger Sensa

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这是一个big-endian little-endian问题.Motorola芯片使用Big-endianIntel芯片使用Little-endian一些信息：http：//www.cs.umass.edu/~verts/cs32/endian.htmlDave Watling -----
原始消息-----来自：Shawn Fessenden [mailto：shawn@testech-ltd.com]发送时间：2005年11月2日14:31：VR​​FSubject：RE：[vrf]字节数组转换为int16s数组>数据是
首先呈现为LSB>而To / From Socket对象>首先假设它是MSB。我的！
嗯，是的，我可以想到一个更快的方式，但我认为更大的问题是，无论发送数据是什么都不正确！
网络字节顺序发布为对应用程序层透明。
IOW，htons（）首先没有被使用。基本上，只需将字节移动到一个Int16数组中。
如果没有其他解决方案在同一时间出现，我会从今天的小方向回来。-SHAWN ----您目前订阅了vrf：watling@icerasemi.com要订阅，请发送空白电子邮件至“join-vrf @
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。
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     以下为原文

  This is a big-endian little-endian issue.

Motorola chips use Big-endian
Intel chips use Little-endian

Some info:
http://www.cs.umass.edu/~verts/cs32/endian.html

Dave Watling


-----Original Message-----
From: Shawn Fessenden [mailto:shawn@testech-ltd.com]
Sent: 02 November 2005 14:31
To: VRF
Subject: RE: [vrf] Array of bytes convert to array of int16s

> the data is presented as LSB first
> whereas the To/From Socket object
> assumes it's MSB first.

Oh my! Well, yes I can think of a faster way but I think the larger
problem
is that whatever is sending the data is incorrect! Network byte order is
supposed to be transparent to the application layer. IOW, htons() was
not
used in the first place.

Basically, just move the bytes into an Int16 array en masse. I'll
elaborate
when I get back from today's little side track if no other solution
presents
itself in the mean time.
-SHAWN-



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谢谢戴夫，我不得不捏一点让这个接受我的数据，但是效果很好。但是，我在套接字读数上坚持了一点，想出了这个：来自Socket，READ BINARY x BYTE ARRAY：16001，
2然后一个公式：（x [*，1] * 256 + x [*，0]）将两列字节结合在一起。非常快速而且非常简单.-- Graeme HiltonR＆amp; D EngineerSchlumberger SensaDavid Watling在02上写了以下内容
/ 11/2005 14:08：>嗨Graeme，>我写了一个byteswop公式，它可以在>一次的数组的所有元素上工作。
将数组加载为INT16，然后运行swopper功能。
您可能>或者可能不想要2的cmpl函数。>>函数byteswop int16：> bitOr（bitAnd（bitShift（A，-8），＃H00ff），bitAnd（bitShift（A，8），＃Hff00））
;>> 2的cmpl> asInt16（A-（A DIV 32768）* 65536）; >>>问候>> David Watling >> -----原始信息----->来自：Graeme Hilton [mailto：GHilton
@ slb.com]>发送时间：2005年11月2日13:43>收件人：VRF>主题：[vrf]字节数组转换为int16s数组>> Hi All，>>这是我最新的谜题; >>我正在阅读数据
来自TCP / IP套接字。
我读取32002个字节>> 16001 16位整数。
我不能使用READ BINARY x INT16 ARRAY1D> 16001，因为>数据首先显示为LSB，而To / From Socket对象假设>它> MSB优先。>>要将这些数字拼接在一起，我将执行以下操作：>
For Each（A [2 * i] + A [（2 * i）+1] * 256）并收集结果以创建我的> int16> 16001元素数组。>>我的问题是这需要大量的
时间（与计划的其余部分相比）。
有没有人有非循环方式这样做或>另一个>节省时间的方法？> ---您目前订阅vrf为：r***@soco.agilent.com要订阅发送空白电子邮件到“join-vrf @
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     以下为原文

  Thanks Dave,

I had to fiddle a little to get this to accept my data, but it works well.

However, I persevered a little more with the socket reading and came up with this:

From Socket, READ BINARY x BYTE ARRAY:16001,2
Then a formula: (x[*,1]*256+x[*,0]) to marry the two columns of bytes together.

Very quick and very simple.

--
Graeme Hilton
R&D Engineer

Schlumberger Sensa


David Watling wrote the following on 02/11/2005 14:08:
> Hi Graeme,
> I wrote a byteswop formula which works on all elements of the array at
> once.  Load the array as INT16, then run the swopper function.  You may
> or may not want the 2's cmpl function as well.
>
> Function byteswop int16:
> bitOr(bitAnd(bitShift(A,-8),#H00ff),bitAnd(bitShift(A,8),#Hff00));
>
> 2's cmpl
> asInt16(A-(A DIV 32768)*65536);
>
>
> Regards
>
> David Watling
>
> -----Original Message-----
> From: Graeme Hilton [mailto:GHilton@slb.com]
> Sent: 02 November 2005 13:43
> To: VRF
> Subject: [vrf] Array of bytes convert to array of int16s
>
> Hi All,
>
> Here's my latest puzzle;
>
> I am reading data from a TCP/IP socket.  I read 32002 bytes which
> represent
> 16001 16-bit integers.  I can't use the READ BINARY x INT16 ARRAY1D
> 16001 as the
> data is presented as LSB first whereas the To/From Socket object assumes
> it's
> MSB first.
>
> To stitch these numbers together I run through the following:
> For Each (A[2*i]+A[(2*i)+1]*256) and collect the results to create my
> int16
> array of 16001 elements.
>
> My problem is that this takes a significant amount of time (compared to
> the rest
>   of the program).  Does anyone have a non-looping way of doing this or
> another
> time-saving method?
>

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