怎么根据传感器输出控制ServoMotor

嗨，我用的是简易脉冲v1.1，一种通过指尖感应脉冲并输出数字脉冲的传感器。我想创建一个中断，它为持续时间x设置一个定时器，并在每次读取5V的数字脉冲时递增计数器，然后重置计数器并等待持续时间y，然后重复该过程。此外，根据计数的脉冲数，我想控制伺服电机。谢谢您。下面是用于将servo.void main(){TRISB=0x00;//PortB移动为Output的延迟例程，而(1){//Gear 1 if(RB0=1){_.(350)；RB0=0；}//Gear 2 if(RB0=1){_.(1330)；RB0=0；}//Gear 3 if(RB0=1){.(2150)；RB0=0；}}}



      以下为原文

    Hi,

I am using easy pulse v1.1, a sensor that senses your pulses through you fingertip and outputs them an digital pulses. I want to create an interrupt that sets a timer for duration x and increment the counter every time it reads a digital pulse of 5V and then resets the the counter and wait for duration y and then repeat the process. Also, according to the number of pulses that were counted, I want to control the servomotor. Thank you. Below is the delay routine for moving the servo.

void main (){
TRISB = 0x00; //PortB as Output
while(1){
//Gear 1
if (RB0=1)
{
_delay(350);
RB0 = 0;
}
//Gear 2
if (RB0=1)
{
_delay(1330);
RB0 = 0;
}
//Gear 3
if (RB0=1)
{
_delay(2150);
RB0 = 0;
}
}