怎么测量不同脉冲信号之间的时差

您好Ganesh，您使用的是Autolevel，还是设置了触发级别？如果没有，我建议尝试设置一个触发级别，看看是否能解决它。



     以下为原文

  Hello Ganesh,

Are you using Autolevel, or are you setting a trigger level?

If not, I suggest trying to set a trigger level and see if that takes care of it.

是的！
看起来已经解决了。我将触发电压值和探头容量从10X更改为1X。只需检查值（每秒一次）的正确性即可找到它，需要检查一天左右确认..



     以下为原文

  Yep! Looks resolved..I Change the trigger voltage values and The Probe Capacitances from 10X to 1X.Just checked the value(one per second) correctness to find its OK, need to check that over a day or so to confirm..

问候Ganesh，这一代计数器自动选择测量结果的单位。
虽然无法直接控制，但您可以使用Scale＆amp;
偏移功能可将您的读数乘以所需系数（即比例= 1,000,000）。
正如笔记一样，这已由许多人提出，我们的新一代计数器设计用于支持用户指定的单位。时间间隔的结果范围规格为-1 ns至10E5秒。
如果第二个通道超过第一个通道不到1 ns，那么您可以得到否定答案。
如果第二个通道超过1 ns导致第一个通道，则计数器将在第一个通道上触发，并使用第二个通道上的下一个边缘作为测量的终点。
您可以使用Scale＆amp;
在这种情况下的偏移功能以及从所有读数中减去一个值（即偏移= -500,000）。如果同时使用比例和偏移，则在比例因子之后应用偏移，并应相应地进行调整:(测量*比例）
+偏移=显示结果



     以下为原文

  Greetings Ganesh,

This generation of counters automatically selects the units for the measured result.  While it cannot be directly controlled, you can use the Scale & Offset function to multiply your readings by the desired factor (ie scale = 1,000,000).  Just as a note, this has been brought up by many people and our newer generation of counters has been designed to support user-specified units.

The specification for the results range of Time Interval is -1 ns to 10E5 seconds.  If the second channel leads the first channel by less than 1 ns, then you can get a negative answer.  If the second channel leads the first channel by more than 1 ns, then the counter will trigger on the first channel and use the next edge on the second channel as the end point of the measurement.  You can use the Scale & Offset function in this situation as well to subtract a value from all readings (ie offset = -500,000).

If you are using both Scale and Offset, the offset is applied after the scale factor and should be adjusted accordingly:
   (Measurement * Scale) + Offset = Displayed Results

亲爱的cldiller，感谢您的回复，如果在其后面板上提供的外部参考10MHz精度为X％，我想知道计数器测量的准确性。任何数学关系？从数据表中不太清楚。注意，
Ganesh神。



     以下为原文

  Dear cldiller ,
                Thanks for Your reply,would like to know the accuracy of the counter Measurements if the external reference 10MHz fed on its back panel is of accuracy is X% .Any Mathematical Relationship?Thats not very clear from the data sheet.

Regards,
Ganesh.

Greetings，Ganesh，使用外部参考时，使用外部参考的规格来代替时基规范。
例如，时间间隔系统不确定性的规范是：“系统不确定性=±（时基误差×测量）±触发电平定时误差±900 ps差分通道误差（53132A）”时基误差是所有的组合
外部参考的规范。
对于53132A内部时基选项，时基误差是温度稳定性加上自上次校准后的老化的总和。
对于某些外部参考，可能还有一些规范可以考虑其他因素，例如电力线的变化，也应包括在内。
有一个示例显示了如何在操作指南中确定总体测量误差，请参阅第3-8页的http://cp.literature.agilent.com/litweb/pdf/53131-90055.pdf。
文档库中还有一些更深入的指南，请访问http://www.agilent.com/find/53132ABest，谢丽尔



     以下为原文

  Greetings, Ganesh,

When using an external reference, the specifications of the external reference are used in place of the Time Base specifications.  For example, the specification for the Time Interval systematic uncertainty is:

"
Systematic uncertainty = ± (Time base error × Measurement) ± Trigger level timing error ± 900 ps Differential channel error (53132A)
"

The Time Base Error is a combination of all the specifications for the external reference.  For the 53132A internal time base options, the timebase error is the sum of the temperature stability plus the aging since the last calibration.  For some external references, there may also be specifications to account for other factors, such as variation in the power lines, that should also be included. 

There is an example showing how to determine the overall measurement error in the Operating Guide at http://cp.literature.agilent.com/litweb/pdf/53131-90055.pdf on page 3-8.  There are also some more in-depth guides in the Document Library at http://www.agilent.com/find/53132A

Best Regards,
Cheryl