在嵌入式主机上使用USB Keyboard方面需要帮助

生命是短暂的，谷歌是Fasthtp://StaskOfFult.COM/Quass/7073328／List-Heal-KeBest-SCAN -CODES-和UB-HID-键盘记录文档搜索，例如：Windows HID键盘代码



      以下为原文

    Life is short, and Google is fast
 
http://stackoverflow.com/questions/27075328/list-of-hex-keyboard-scan-codes-and-u***-hid-keyboard-documentation
 
search e.g. for:   windows hid keyboard codes

您好，感谢您的回复和链接到网站；我现在有所有的键盘代码，这是伟大的。虽然我现在有了Shift KEY（0xE1）的代码，但是我仍然不能让它工作，因为修改键必须以一种特殊的方式使用，而且C代码对于我来说还远远不够。但是，不管怎样，我可以继续进行这个项目，因为我需要大约50个不同的密钥，并且不关心W。它们是帽子。所以我现在所有的代码都不需要使用Shift键，再次感谢你们的帮助。肯。



      以下为原文

    Hello,
Thanks for reply and link to websites; I now have all the keboard codes,
which is great.  But although I now have the code for Shift key (0xE1)
I still cannot get it to work, because the modifier keys have to be
used in a special way, and the C code for this is still beyond my grasp.

However, no matter, I can get on with the project because I need approx
50 different keys, and don't care what they are.  So all the codes I now
have will be plenty without using the Shift key.

Thanks again for your help.  Ken.

修饰符进入包的第一字节，这是6（或8）个键的位字段。键入3…8字节。



      以下为原文

    Modifiers go into the 1st byte of the packet, which is a bitfield for 6 (or 8) keys. Keys go into 3..8 bytes.

您忽略了引用：在链接到的第一页。



      以下为原文

   
You ignored the reference to:
Byte 0: Keyboard modifier bits (SHIFT, ALT, CTRL etc)
in the first page linked to.

您好，谢谢您的进一步回复。我知道修改器必须在包中的一个特殊位置，但不能弄清楚这是如何从MLA中得到的代码中实现的。它似乎把普通的关键数据放在数组索引0中，例如在这行中：输入报告。键[0 ] = sEndoKIKE；/ /设置关键字PRESI认为上面涉及到什么叫做结构？我只掌握C的基本知识，不理解结构是如何工作的，所以也许我应该把它放在这里，继续我的项目，也许以后我会抽出时间去学习一些更高级的C。



      以下为原文

    Hello,

Thanks for further replies.
I was aware that modifiers have to go in a special place in the packet,
but cannot work out how this is implemented in the code I have got
from MLA.  It seems to put the normal key data in array index 0, eg as in
this line:

           inputReport.keys[0] = send_key;  // Set the key press

I think the above relates to what is called a structure ?
I have only a basic knowledge of C, and do not understand how structures work.

So perhaps I should just leave it at that, press on with my project, and
maybe later I will find time to learn some more advanced C.
Thanks again.

代码不适合C初学者，我同意。我没有跳进那个样本，我不能测试任何东西。但是，如果你想继续：这是从你的AppIdEclipse键盘。C和我在AppHyKeBoad任务中间添加了一条线，这应该是添加修饰符的方法（如左撇子）。请注意，在“联合修饰符”中可以看到其他修饰符。当然，您不希望为所有键设置修改器，这只是语法的一个例子。它将重置结构为零，从而重置先前设置在这个全局变量中的任何位。



      以下为原文

    The code is not well suited for C beginners, I agree.
I did not dive into that sample and I cannot test anything. But if you want to continue:
 
This is from your app_device_keyboard.c and I added a line in the middle of APP_KeyboardTasks which should be the way to add the modifiers (leftAlt as example) here.   See the other modifiers in the union 'modifiers'.
Note that of course you do not want to set the modifier for all keys, it's only an example for the syntax.
 
 

 
 union __attribute__((packed))
    {
        uint8_t value;
        struct __attribute__((packed))
        {
            unsigned leftControl    :1;
            unsigned leftShift      :1;
            unsigned leftAlt        :1;
            unsigned leftGUI        :1;
            unsigned rightControl   :1;
            unsigned rightShift     :1;
            unsigned rightAlt       :1;
            unsigned rightGUI       :1;
        } bits;
    } modifiers;
 
 
        memset(&inputReport, 0, sizeof(inputReport));

        if(BUTTON_IsPressed(BUTTON_USB_DEVICE_HID_KEYBOARD_KEY) == true)
        {
            if(keyboard.waitingForRelease == false)
            {
                keyboard.waitingForRelease = true;

                /* Set the only important data, the key press data. */
                inputReport.keys[0] = keyboard.key++;
                inputReport.modifiers.bits.leftAlt = 1;   // added by rodims for test
                        

                //In this simulated keyboard, if the last key pressed exceeds the a-z + 0-9,
                //then wrap back around so we send 'a' again.
                if(keyboard.key == 40)
                {
                    keyboard.key = 4;
                }
            }
 
       }
 
 
 
memset(&inputReport, 0, sizeof(inputReport));

你好，我刚才试过你的建议，罗迪姆斯，用左移而不是左撇子，效果不错！当设置为0时，它给出小写，当设置为1时，大写字母。同样地，对于其他所有的钥匙，我怀疑是否有任何办法能为我自己解决这个问题。多谢，肯。



      以下为原文

    Hello again,
I have just tried your suggestion, rodims, using leftShift rather than leftAlt, and it works!
When set to 0 it gives lower case, and when set to 1, upper case. Similarly for all the other keys.
I doubt if there is any way I could have worked this out for myself.
 
Many thanks,   Ken.