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您好,我很好奇33502A隔离放大器的工作频率范围。
看看规格,看起来它可能只适用于低频。 另一方面,它看起来像是安捷伦函数发生器的附加组件,它具有广泛的频率范围。 -Nate 以上来自于谷歌翻译 以下为原文 Hello, I am curious about the working frequency range for the 33502A Isolated Amplifier. Looking at the specs, it looks like it might be only for low frequencies. On the other hand, it looks like it is meant as an add-on to Agilent function generators, which have a broad frequency range. -Nate |
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您好Nate,它与33500系列发电机配对良好,但33502A适用于低频。
它可以在100kHz输出高达50VPP,在300kHz输出-3dB点。 300kHz后性能会很快下降。 您受到大于20V / us的压摆率的限制。放大器行业将全功率带宽定义为可以在没有明显的回转失真的情况下进行正弦波的最大频率。 小信号是小到足以不受回转影响的信号的带宽(通常为-3db),仅为幅度的线性减小器。 无需回转即可输出的300kHz最大输出为10.6 Vpk。 我选择了300kHz,因为它是我们在数据手册中描述的小信号带宽。 压摆率= 2 * pi * f * VPk然后除以1E6,将其置于V / uS示例2 * 3.14159 * 300E3 * 10.6 = 19.98E6 V / S等于19.98V / us假设您要输出12VPP 。 您可以计算出可以输出12VPP(6Vpk)的最大频率。 20V / us = 2 * pi * f * 6 / 1E6 f = 20E6 /(12 * pi)= 530.52 kHz这也适用于正弦波,并记住幅度线性减小,因此需要输入电压 在这个频率下输出12VPP并不是一个简单的12VPP / 5。 您必须使用输入电压,直到输出结果为所需的12VPP。 以上来自于谷歌翻译 以下为原文 Hello Nate, It does pair well with the 33500 series generators, however the 33502A is for low frequencies. It can output up to 50VPP at 100kHz and a -3dB point at 300kHz. Performance drops off very quickly after 300kHz. You are limited by the slew rate which is >20V/us The industry for amplifiers defines full power bandwidth as the maximum frequency you can do a sine wave without significant slewing distortion. Small signal is the bandwidth (usually -3db) for signals that are small enough to not be affected by slewing, only linear reducers of amplitude. The max output at 300kHz that you can output without slewing is 10.6 Vpk. I chose 300kHz because it is the small signal bandwidth we characterized in the data sheet. Slew rate = 2*pi*f * VPk Then you divide by 1E6, to put it in V/uS Example 2*3.14159*300E3*10.6 = 19.98E6 V/S Which equals 19.98V / us Let’s say you want to output 12VPP. You could calculate the max frequency that you can output 12VPP (6Vpk). 20V/us = 2*pi*f *6/1E6 f = 20E6/(12*pi) = 530.52 kHz Again this is for a sine wave, and remember there is a linear reduction in amplitude, so the voltage you need to input to get 12VPP out at this frequency is not a simple 12VPP/5. You will have to play with the input voltage until your output result is the desired 12VPP. |
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