如何从MCC生成的中断例程中调用“main.c”中的函数

是的，这是一个旧版本的XC8的问题，我认为已经完全解决了一段时间前。你尝试的是不可能的标准XC8设置（“编译堆栈”）。如果代码大小不是问题，我建议创建一个从ISR调用的函数的副本，用“ISRZ”预先装入函数名。这样你就可以编译了。



      以下为原文

    Yep.
This was an issue with older versions of XC8 I thought had been solved completely starting some time ago.
What you try is not possible with the standard XC8 settings ("compiled stack"). If code size is no issue, I'd suggest to create a copy of the function(s) to be called from the ISR, prefixing the function name with "ISR_". This way you should be able to compile.

寻找另一种方式。中断是不理想的。



      以下为原文

    Find another way.
calling funcs. from interrupts is not ideal.

谢谢你的回复。好吧，接受你必须在ISR中快速，并调用一个函数不是一个好方法。那么你的建议是什么？（结构设计明智）尝试制作一个发射机，调频，发送20×150个不同的频率包。吨跳过细节，为开始35US发送默认FRQ，但为每一个150美元时隙设置一个新的FRQ。这个发送应该在ZC（零交叉）和ZC之后（用Time2）完成。



      以下为原文

    Thank you for your replies.
Ok, accept that you have to be quick in an ISR and calling a function is not a good way.
 
Then what is your proposal for this: ( structural design wise )
 
Trying to make a transmitter, FM, sending 20 x 150us different frequency packets.
Here is the funstions in the main.c, just skip the details, for the starting 35us sending default freq but for each 150us slot setting a new freq. This sending should be done on ZC (zero cross) and after ZC ( with timer2 ).
 

void TX_block(){
    if (flags.tx_enb==1){
        TMR1H = 251; TMR1L = 224; //35us
        TMR1_StartTimer();
        CCP1CONbits.EN = 1;
        tx_nbl_cnt=0;
        flags.tx_enb=0;
    }

}

//1st TX-slot
void ZCD_int(){
    TX_block();
}

//after ZCD 6ms, 2nd TX-slot
void TMR2_int(){
    TX_block();
}

//tx - next nibble - 150us
void TMR1_int(){
    ++tx_nbl_cnt;
    if(tx_nbl_cnt <= packets_tosend){
        if(tx_nbl_cnt==1) TMR1H = 238; TMR1L = 128; //150us
        T4PR = tx_packet[tx_nbl_say-1] + 64;
    } else if (tx_nbl_cnt>packets_tosend) {
        CCP1CONbits.EN = 0;
        TMR1_StopTimer();
    }
}


/*
                         Main application
 */
void main(void)
{
    // initialize the device
    SYSTEM_Initialize();

    TMR2_SetInterruptHandler(TMR2_int);
    TMR1_SetInterruptHandler(TMR1_int);
    ZCD_SetInterruptHandler(ZCD_int);
    
    // Enable the Global Interrupts
    INTERRUPT_GlobalInterruptEnable();

    // Enable the Peripheral Interrupts
    INTERRUPT_PeripheralInterruptEnable();

    while (1)
    {
        delay_10ms (200);
        IO_RC3_SetHigh();
        
        flags.tx_enb=1;
        
        delay_10ms(2);
        IO_RC3_SetLow();
    }
}
 

你并不总是需要中断。启动计时器并等待定时器标志设置。“你的建议是什么？”你可能已经花了好几个小时了，我无法用一个回复来解决这个问题。我甚至不知道你是如何传输OTA的。你发送的是24/7吗？如果我在做广播的话，我不会为8位而烦恼，但这是我的观点。



      以下为原文

    You don't always need interrupts.
Start the timer and wait for the timer flag to be set.
 
"What is your proposal?"
You may have spent hours on it, I can't fix that with one reply.
I don't even know how you are transmitting ota.
Are you transmitting 24/7?
 
If I was doing radio stuff, I wouldn't bother with 8bit but that is my opinion.

2个不同时期的阶段同步？这是另一个整数倍吗？否则，这是不可能的。



      以下为原文

    2 different periods constantly in phase??
Is the one an integer multiple of the other? Otherwise this would not be possible.