PIC18F27K40会触发它的中断并运行TMR0 ISR吗

PIC18F27 K40HI，函数A—我使用TMR0作为程序的慢周期计数器。一旦TMR0上指定数量的“蜱”已经通过，那么采取一些行动。TMR0的全部计数（16位）最多是分钟。函数B—I也使用TMR0（重新编程它的配置）作为长时间设备来唤醒设备从睡眠。TMR0的整个计数可以是半天……当它在函数A中使用并命中它的末端时，它会触发它的中断并运行TMR0 ISR，对吗？在我思考的这个阶段，TMR0ISR会简单地重置计时器并重新启动它。程序将从它被粗暴地中断的地方继续。当它被用作函数B中的睡眠中断器时，它会在计数结束时触发它的中断，并且…我正在考虑触发它的中断，然后触发我的睡眠数据的重置，如我的数据表第8.13部分所述，叫做“确定重置的原因”（pp.81.）。在那里它说程序计数器在PC+ 2。这是否意味着它将不运行TMR0 ISR而是跳到第二个指令之后的睡眠（）；指令？在这一点上，我应该检查状态寄存器的TO和PD位状态，然后跳转到适当的程序？谢谢，史提夫



      以下为原文

    PIC18F27K40

Hi,
Function A - I'm using TMR0 to act as a slow period counter for parts of the program.  ie. once a specified number of 'ticks' on TMR0 have passed then take some action.  The whole count (16bits) of TMR0 would be minutes at best.
Function B - I'm also using TMR0 (after re-programming its configuration) as a long time period device to wake up the device from sleep.  The whole count of TMR0 could be half a day...

So.

When it is being used in Function A and hits its end, it will fire its interrupt and run the TMR0 ISR right ?  At this stage of my thinking TMR0 ISR would simply reset the timer and restart it.  The program would continue from where it was rudely interrupted.

When it is being used as a sleep interrupter in Function B, it fires its interrupt at the count end and ... ?  I am thinking the firing of its interrupt then triggers a reset from sleep as described in section 8.13 of my datasheet called "Determining the Cause of a Reset" (pp.81).  In there it speaks of the program counter being at PC+2.  Does that mean it will not run TMR0 ISR but jump to the second instruction after the Sleep(); instruction ?  At which point I should check the STATUS register for TO and PD bit status and then jump into program proper ?

Thanks,
Steve