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嗨,我想用功率扫描完成增益测量。
我期待~44 dB的增益,但我看到-10 dB的损失! 扫描功率低= - 45 dBm,扫描功率高= 10 dBm。 通过校准确认完成,频率为80.5 MHz。 频率“扫描”(80.5 MHz,零扫宽)显示预期的增益值。 我究竟做错了什么? 谢谢,格雷格 以上来自于谷歌翻译 以下为原文 Hi, I'd like to complete gain measurements, using a power sweep. I expect ~ 44 dB of gain, but I'm seeing losses of -10 dB! Sweep power low = - 45 dBm, Sweep power high = 10 dBm. A confirmed through calibration was finished, at 80.5 MHz. A frequency "sweep" (80.5 MHz, zero span) shows expected gain values. What am I doing wrong? Thanks, Greg |
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6个回答
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如果您能告诉我们您正在使用的分析仪的型号和固件版本,将会很有帮助。
还描述了您的测试设置(连接到分析仪的外部物理硬件)。 如果您的设备确实具有44 dB的增益并且您将输入功率一直扫至+10 dBm,那么放大器的输出将为+50 dBm(假设有一些压缩)。 如果放大器输出端没有外部高功率焊盘,那么远高于任何分析仪的损坏等级。 以上来自于谷歌翻译 以下为原文 it would be helpful if you could tell us the model number and firmware revision of the analyzer you are using. also a description of your test setup (external physical hardware connected to the analyzer). if your device really does have 44 dB of gain and you sweep the input power all the way up to +10 dBm, then the output of your amp would be around +50 dBm (assuming some compression). That is well above damage level for any analyzer if there is no external high power pad at the output of the amp. |
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Topcbpcba 发表于 2018-9-27 07:31 嗨,谢谢你的回复! 我使用的是5072B,放大器的输出衰减为50 dB。 我不明白,我错过了什么。 在扫描之前执行并验证直通校准。 此外,我可以使用频率扫描确定增益。 再次感谢! 以上来自于谷歌翻译 以下为原文 Hi and thanks for your reply! I'm using a 5072B, and the amp has 50 dB of attenuation on the output. I don't understand, what I'm missing. A through calibration is performed and verified, before a sweep. Furthermore, I can determine the gain, using a frequency sweep. Thanks again! |
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发布带有扫描结果的图表。 在图上一定要包括以下迹线:S21 R1(输入功率)B(输出功率)S11然后我们可以看到结果并解决问题。 用于校准:不进行任何校准。 从未校准的测量开始,并显示上面的4条迹线。 他们有道理吗? (VNA应该在测试端口具有精确到0.5 dB的因子cal,因此你的增益将偏离电缆损耗,这应该是非常小的。如果未校准的测量看起来很糟糕,那么我们有一个问题, 如果它看起来不错,我们还有另外一个。你说放大器输出端有一个大衰减器,校准中是否包含衰减器?如果你阅读我关于去嵌入大衰减器的章节,你可以看到那里存在数值问题 。 以上来自于谷歌翻译 以下为原文 Post a plot with the results of your sweep. On the plot be sure to include the following traces: S21 R1 (input power) B (output power) S11 Then we can see the results and sort out the issue. For calibration: don't do any calibration. Start with an uncalibrated measurement and show the 4 traces above. Do they make sense? (the VNA should have a factor cal that is accurate to about 0.5 dB at the test port, so your gain will be off the cable loss which should be quite small as well. If the uncalibrated measurement looks bad, then we have one issue, if it looks good, we have another. You say the amplifier has a large attenuator on the output, is the attenuator included in the calibration? If you read my chapter on de-embedding large attenuators, you can see that there numerical problems with that. |
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亲爱的Greg,下面的E5072A应用笔记和放大器测量向导也可以帮助您测量放大器增益。 http://literature.cdn.keysight.com/litweb/pdf/5990-9974EN.pdf http://www.keysight.com/main/editorial.jspx?ckey=1395678&id=1395678&nid=-11143.0。 00& lc = eng& cc = US如果您与我们分享详细的测量设置,它也将对我们有所帮助。 以上来自于谷歌翻译 以下为原文 Dear Greg, The application note and amplifier measurement wizard for E5072A below will also help you measure amplifier gain. http://literature.cdn.keysight.com/litweb/pdf/5990-9974EN.pdf http://www.keysight.com/main/editorial.jspx?ckey=1395678&id=1395678&nid=-11143.0.00&lc=eng&cc=US It will also help us if you shared detailed measurement setup with us. |
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大洼球王 发表于 2018-9-27 08:05 感谢大家的帮助。 R1和B曲线对我来说是新的,因为我通常使用没有它们的5061A。 但是5072确实如此! 我已被跟踪了一段时间,所以我不会在这几天。 我一定会告诉你我的进展情况。 再次感谢,格雷格 以上来自于谷歌翻译 以下为原文 Thank you all for your help. The R1 and B traces are new to me, since I ordinarily use a 5061A that doesn't have them. The 5072 does, though! I've been side tracked, for a bit, so I won't be on this for a few days. I'll be sure to keep you posted on my progress. Thanks again, Greg |
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我回来了,一切都很好。 由于无知,我的问题是没有设置CW频率。 我把它保留在默认的300 kHz,而不是放大器的工作频率。 增益曲线很漂亮,加上输出衰减后,功率曲线也是如此。 再次感谢您的帮助! 以上来自于谷歌翻译 以下为原文 I'm back, and all is well. My problem, due to ignorance, was not setting the CW frequency. I left it at the default 300 kHz, instead of the operating frequency of the amplifiers. The gain curve is beautiful, and after adding in output attenuation, the power curve is too. Thanks again for all of your help! |
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