转换是功率方程式P = EI，或者因为您只有电压P（瓦特）=电压^ 2 x电阻（欧姆）。
dBm是以dB为单位的功率，以0.001瓦为参考。
所以P（dBm）= 10 x log（P（瓦特）/ 0.001（瓦特））。如果你试图计算11683A的输出不确定性，这是一个非常复杂的问题，在讨论论坛上不容易解释。
我建议您拨打1-800-829-4444致电安捷伦的在线技术支持团队。
祝你好运！
以上来自于谷歌翻译
以下为原文
The conversions are the power equations P=EI or since you only have the voltage it would be P (watts) = voltage^2 x resistance (ohms). dBm is the power in dB as referenced to 0.001 watts. So the P (dBm) = 10 x log (P (watts) / 0.001 (watts)).
If you are trying to calculate the output uncertainty of the 11683A, this is a very complex issue, not easily explained over a discussion forum. I would recommend that you call Agilent's online technical supprt team at 1-800-829-4444. Good luck!
转换是功率方程式P = EI，或者因为您只有电压P（瓦特）=电压^ 2 x电阻（欧姆）。
dBm是以dB为单位的功率，以0.001瓦为参考。
所以P（dBm）= 10 x log（P（瓦特）/ 0.001（瓦特））。如果你试图计算11683A的输出不确定性，这是一个非常复杂的问题，在讨论论坛上不容易解释。
我建议您拨打1-800-829-4444致电安捷伦的在线技术支持团队。
祝你好运！
以上来自于谷歌翻译
以下为原文
The conversions are the power equations P=EI or since you only have the voltage it would be P (watts) = voltage^2 x resistance (ohms). dBm is the power in dB as referenced to 0.001 watts. So the P (dBm) = 10 x log (P (watts) / 0.001 (watts)).
If you are trying to calculate the output uncertainty of the 11683A, this is a very complex issue, not easily explained over a discussion forum. I would recommend that you call Agilent's online technical supprt team at 1-800-829-4444. Good luck!
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