大家好,
我试着了解LIS3DSH加速度计的实际可用分辨率是多少,因为我需要对其进行评估以进行透视测量。
从数据表我可以读取PSD = 150ug / sqrt(Hz)@ ODR = 100 Hz然后BW = 50 Hz
对于带有单极点滤波器的模拟输出,总噪声可以计算为PSD * SQRT(1.57 * BW),假设使用相同的计算我们有150ug * SQRT(78.5)= 1.33mg,灵敏度等于0.06 mg /数字@±2g我们有:
1.33mg / 0.06mg /位= 22.16位错误,然后理论上的16位我们应该有65536 / 22.16 = 2957.4位,大约相当于最终分辨率的11-12位。
我恳请问这是一种正确的模式,通过考虑噪音的影响或者如果我错过了一些点来估计真实的最终分辨率,那么可能是执行此计算的正确方法。
希望有人能指出我正确的方向。
在此先感谢
最好的祝福
法比奥
以上来自于谷歌翻译
以下为原文
Hi all,
I'm try to understand what can be the real usable resolu
tion of the LIS3DSH accelerometer because I need to evaluate it for inclometric measurements.
From the datasheet I can read a PSD=150ug/sqrt(Hz) @ ODR=100 Hz then BW=50 Hz
For a analog output with one single pole filter the overall noise can be calculated as PSD*SQRT(1.57*BW),supposing to use same calculation we have 150ug*SQRT(78.5)=1.33mg, having a sensitivity equal to 0.06 mg/digit @ ±2g we have:
1.33mg/0.06 mg/digit = 22.16 digit of error then instead the theoretical 16 bit we should have 65536/22.16=2957.4 digit which is approx equivalent to 11-12 bit of final resolution.
I kindly ask if this is a correct mode to estimate the real final resolution by taking in account the effect of the noise or if I missing some point and then what can be the correct way to perform this calculation.
Hope someone can point me in the correct direction.
Thanks in advance and
best regards
Fabio