使用PLTS进行时域测量不确定Step是什么意思？

步长是resposne的时间增量。
它是时间跨度除以点数。
分辨率约为1 /频率跨度，因此任何比该数字窄的步骤实际上都是结果的插值。
您可以这样思考：分辨率告诉您可以看到的最大坡度或上升时间;
如果您的时间跨度足够小，因此步长小于重新生成，则该步骤表示由分辨率限制的平滑响应。



     以下为原文

  Step is the time increment of the resposne.   It is the time span divided by the number of points.  

the resolution is about 1/frequency span, so any step narrower than that number really is an interpolation of the results.  You can think about it this way:

The resolution tells you the maximum slope or rise time that you can see; if you your time span is small enough so the step is smaller than the resoultion, the step represents a smoothed response limited by resolution.

Hello SN：在PLTS中，我们插入freq域数据以确保IFFT之前的（freq start = freq步骤）。
在你的情况下，freqStart = 0.01GHz，freqStop = 26.5GHz，NOP = 201，freqStep =（26.5 - 0.01）/ 200 = 0.13245GHz插值后，freqStart = 0.13245GHz，freqStep = 0.13245GHz，freqStop = 26.5GHz，NOP =
floor（（26.5 - 0.13245）/0.13245 + 1）= 200来自IFFT的时域数据实际上在原始测量中有200个点而不是201个点。
时间步长=（3.78 - 0）/ 199 = 0.01899ns = 18.99ps，非常接近你看到的18.97ps。
0.02ps差异的原因是时间停止略小于3.78，我们将其四舍五入为3.78（2位数）。



     以下为原文

  Hello SN:

In PLTS, we interpolate the freq domain data to ensure the ( freq start = freq step) before IFFT. In your case,
freqStart = 0.01GHz, freqStop = 26.5GHz, NOP = 201, freqStep = (26.5 - 0.01) / 200 = 0.13245GHz

After interpolation,
freqStart = 0.13245GHz, freqStep = 0.13245GHz, freqStop = 26.5GHz, NOP = floor((26.5 - 0.13245) / 0.13245 + 1) = 200

The time domain data from IFFT actually has 200 points rather than 201 points in your original measurements. The time step = (3.78 - 0) / 199 = 0.01899ns = 18.99ps, very close to the 18.97ps you saw. The reason for the 0.02ps difference is that the time stop is a little smaller than 3.78, we round it to 3.78 for 2 fractional digits.