我要说的第一件事就是“获得一个抖动包”。
它适用于您的范围，并将使您的生活更轻松。
抖动包是示波器SW的一部分，因此您可以轻松打开短期许可证并进行试用。
我无法从你的照片中确切地知道这是什么。
它是正弦波下降沿的交叉点吗？
如果是这样，那就是测量抖动的最坏方法，即使它是抖动测量包变得可用且易于使用之前的唯一方法。
使用此方法会丢失许多抖动组件。
此外，存储器深度无关紧要，因为示波器仅查看相对于触发器的单个交叉点。
为了解决你的信息中的一些具体问题： - “但是，如果我没有弄错，RMS抖动是rms偏离理想转换，意味着零均值”平均值可能是也可能不是零。
系统中的抖动可能不是完全高斯的。
它可能有DJ组件，或者交叉点可能与理想位置有正偏移或负偏移。
如果抖动不是高斯，则RMS值没有意义。
抖动工具将高斯分量与非高斯分量分开，并分别使用它们来得出总抖动的良好估计。
- “触发抖动在多大程度上影响测量 - 限制是什么？我确信200fs测量是准确的吗？”
200fsec规格是准确的。
很多工作都能够将触发抖动降低到极少数。
您可以使用与用于进行“抖动”测量的相同技术自行测量。
在真正的抖动测量中，触发器没有任何意义或影响，并且不用于测量。
重要的是交叉点相对于理想的时间，无论是“明确的”还是计算的。
免责声明：为了获得更可靠的响应，您应该考虑致电当地的安捷伦技术呼叫中心。
安捷伦论坛在“可用”的基础上进行监控，并不一定是解决技术问题的最快方式。
以上来自于谷歌翻译
以下为原文
First thing I'll say is, "Get a Jitter Package". It's available for your scope, and will make your life so much easier. The jitter package is part of the scope SW, so you could easily turn on a short-term license and try it out.
I can't tell from your picture exactly what this is. Is it the crossing point of the falling edge of the sine wave? If so, that's about the worst way of measuring jitter, even though it was the only way before jitter measurement packages became available and easy to use. There are many jitter components that will get missed using this method. Also, memory depth won't matter, since the scope is only looking at a single crossing point relative to the trigger.
To address some specific issues in your message:
- "However, if I'm not mistaken, RMS Jitter is the rms deviation from the ideal transition, meaning having zero mean"
The mean may or may not be zero. The jitter in your system may not be completely Gaussian. It may have DJ components, or the crossing may have a positive or negative offset from the ideal location. If the jitter is not Gaussian, then the RMS value has no meaning. The Jitter tools separate the Gaussian components from the non-Gaussian components, and use them separately to come up with a good estimate of the Total Jitter.
- "To what extent the trigger jitter affects the measurement-what are the limits? Am I assured that a 200fs measurement is accurate?"
The 200fsec specification is accurate. A lot of work went into being able to reduce the trigger jitter to a very small number. You could measure it yourself using the same technique you used to make your "jitter" measurement.
In a true jitter measurement, the trigger has no meaning or effect and is not used in the measurement. All that matters is the timing of the crossing points relative to the ideal, whether that's 'explicit' or calculated.
Al
Disclaimer: For more reliable response, you should consider calling your local Agilent Technical Call Center. The Agilent Forums are monitored on an "as available" basis, and aren't necessarily the fastest way to get technical questions answered.
我要说的第一件事就是“获得一个抖动包”。
它适用于您的范围，并将使您的生活更轻松。
抖动包是示波器SW的一部分，因此您可以轻松打开短期许可证并进行试用。
我无法从你的照片中确切地知道这是什么。
它是正弦波下降沿的交叉点吗？
如果是这样，那就是测量抖动的最坏方法，即使它是抖动测量包变得可用且易于使用之前的唯一方法。
使用此方法会丢失许多抖动组件。
此外，存储器深度无关紧要，因为示波器仅查看相对于触发器的单个交叉点。
为了解决你的信息中的一些具体问题： - “但是，如果我没有弄错，RMS抖动是rms偏离理想转换，意味着零均值”平均值可能是也可能不是零。
系统中的抖动可能不是完全高斯的。
它可能有DJ组件，或者交叉点可能与理想位置有正偏移或负偏移。
如果抖动不是高斯，则RMS值没有意义。
抖动工具将高斯分量与非高斯分量分开，并分别使用它们来得出总抖动的良好估计。
- “触发抖动在多大程度上影响测量 - 限制是什么？我确信200fs测量是准确的吗？”
200fsec规格是准确的。
很多工作都能够将触发抖动降低到极少数。
您可以使用与用于进行“抖动”测量的相同技术自行测量。
在真正的抖动测量中，触发器没有任何意义或影响，并且不用于测量。
重要的是交叉点相对于理想的时间，无论是“明确的”还是计算的。
免责声明：为了获得更可靠的响应，您应该考虑致电当地的安捷伦技术呼叫中心。
安捷伦论坛在“可用”的基础上进行监控，并不一定是解决技术问题的最快方式。
以上来自于谷歌翻译
以下为原文
First thing I'll say is, "Get a Jitter Package". It's available for your scope, and will make your life so much easier. The jitter package is part of the scope SW, so you could easily turn on a short-term license and try it out.
I can't tell from your picture exactly what this is. Is it the crossing point of the falling edge of the sine wave? If so, that's about the worst way of measuring jitter, even though it was the only way before jitter measurement packages became available and easy to use. There are many jitter components that will get missed using this method. Also, memory depth won't matter, since the scope is only looking at a single crossing point relative to the trigger.
To address some specific issues in your message:
- "However, if I'm not mistaken, RMS Jitter is the rms deviation from the ideal transition, meaning having zero mean"
The mean may or may not be zero. The jitter in your system may not be completely Gaussian. It may have DJ components, or the crossing may have a positive or negative offset from the ideal location. If the jitter is not Gaussian, then the RMS value has no meaning. The Jitter tools separate the Gaussian components from the non-Gaussian components, and use them separately to come up with a good estimate of the Total Jitter.
- "To what extent the trigger jitter affects the measurement-what are the limits? Am I assured that a 200fs measurement is accurate?"
The 200fsec specification is accurate. A lot of work went into being able to reduce the trigger jitter to a very small number. You could measure it yourself using the same technique you used to make your "jitter" measurement.
In a true jitter measurement, the trigger has no meaning or effect and is not used in the measurement. All that matters is the timing of the crossing points relative to the ideal, whether that's 'explicit' or calculated.
Al
Disclaimer: For more reliable response, you should consider calling your local Agilent Technical Call Center. The Agilent Forums are monitored on an "as available" basis, and aren't necessarily the fastest way to get technical questions answered.
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