如何使用ADS2009找到两点之间的阻抗

hiiiiiiiiiiiiiiiiiii我需要在广告中设计一个使用dsp块的电路???????
谁能帮我？



     以下为原文

  hiiiiiiiiiiiiiiiiiiiii

i need to design a circuit using dsp blocks in ads???????

can anyone help me?

hiiiiiiiiiiiiiiiiiii我需要在广告中设计一个使用dsp块的电路???????
谁能帮我？



     以下为原文

  hiiiiiiiiiiiiiiiiiiiii

i need to design a circuit using dsp blocks in ads???????

can anyone help me?

受到警告

嗨，做一个适当的2端口S参数模拟，看看-Y21，相应导纳矩阵的非对角线元素，可以通过Y = stoy（S）轻松计算，请记住导纳矩阵
与PI网络结构直接相关。
因此，您到点之间的串联阻抗由Zs = - 1 / Y21给出请注意减号。
这不是一个错字。
此致，托比



     以下为原文

  Hi,

do a proper 2-port S-parameter simulation and have a look on -Y21, the off-diagonal element of the corresponding admittance matrix, which can be calculated easily by 
Y=stoy(S)
Keep in mind that an admittance matrix correlates directly with a PI network structure. Therefore, your series impedance between 
to points is given by
Zs= - 1 / Y21
Please pay attention to the minus sign. It's not a typo.

Regards,
Toby