请问EDMA如果是手动触发的话，单核能否开启两个channel进行传输？为什么？

if (CSL_edma3Init(&context) != CSL_SOK)
[
printf ("Error: EDMA module initialization failedn");
]

hModule = CSL_edma3Open(&edmaObj, INSTNUM, NULL, &status);
if ( (hModule == NULL) || (status != CSL_SOK))
[
printf ("Error: EDMA module open failedn");
]

chAttr.regionNum = CSL_EDMA3_REGION_GLOBAL; /*GLOBAL*/
chAttr.chaNum= 0;
hChannel1 = CSL_edma3ChannelOpen(&chObj, INSTNUM, &chAttr, &status);
if ((hChannel1 == NULL) || (status != CSL_SOK))
[
printf ("Error: Unable to open EDMA Channel:%dn", 0);
]
chAttr.chaNum= 1;
hChannel2 = CSL_edma3ChannelOpen(&chObj, INSTNUM, &chAttr, &status);
if ((hChannel2 == NULL) || (status != CSL_SOK))
[
printf ("Error: Unable to open EDMA Channel:%dn", 1);
]
if (CSL_edma3HwChannelSetupQue(hChannel1,CSL_EDMA3_QUE_0) != CSL_SOK)
[
printf ("Error: EDMA channel setup queue failedn");
]
if (CSL_edma3HwChannelSetupQue(hChannel2,CSL_EDMA3_QUE_0) != CSL_SOK)
[
printf ("Error: EDMA channel setup queue failedn");
]
CSL_edma3MapDMAChannelToParamBlock (hModule, 0, 0);
CSL_edma3MapDMAChannelToParamBlock (hModule, 1, 1);
Param0= CSL_edma3GetParamHandle(hChannel1, 0, &status);
if (Param0 == NULL)
[
printf ("Error: EDMA Get Parameter Entry failed for paramID.n");
]
Param1= CSL_edma3GetParamHandle(hChannel2, 1, &status);
if (Param1 == NULL)
[
printf ("Error: EDMA Get Parameter Entry failed for paramID.n");
]
myParamSetup.option = CSL_EDMA3_OPT_MAKE(CSL_EDMA3_ITCCH_DIS,
CSL_EDMA3_TCCH_DIS,
CSL_EDMA3_ITCINT_DIS,
CSL_EDMA3_TCINT_EN,
0, CSL_EDMA3_TCC_NORMAL,
CSL_EDMA3_FIFOWIDTH_NONE,
CSL_EDMA3_STATIC_DIS,
CSL_EDMA3_SYNC_AB,
CSL_EDMA3_ADDRMODE_INCR,
CSL_EDMA3_ADDRMODE_INCR );

myParamSetup.srcAddr = (Uint32)DDR;//源地址
myParamSetup.aCntbCnt = CSL_EDMA3_CNT_MAKE(4,512);//因为传输的是Uint32，所以每次array跳变是4byte，一共跳变512
myParamSetup.dstAddr = (Uint32)mem;//目的地址，L2地址必须用全局地址
myParamSetup.srcDstBidx = CSL_EDMA3_BIDX_MAKE(4,4);
myParamSetup.linkBcntrld= CSL_EDMA3_LINKBCNTRLD_MAKE(0xFFFF,0);//无link
myParamSetup.srcDstCidx = CSL_EDMA3_CIDX_MAKE(0,1);
myParamSetup.cCnt = 1;
if(CSL_edma3ParamSetup(Param0,&myParamSetup) != CSL_SOK)
[
printf ("Error: EDMA Parameter Entry Setup failedn");
]
myParamSetup.option = CSL_EDMA3_OPT_MAKE(CSL_EDMA3_ITCCH_DIS,
CSL_EDMA3_TCCH_DIS,
CSL_EDMA3_ITCINT_DIS,
CSL_EDMA3_TCINT_EN,
1, CSL_EDMA3_TCC_NORMAL,
CSL_EDMA3_FIFOWIDTH_NONE,
CSL_EDMA3_STATIC_DIS,
CSL_EDMA3_SYNC_AB,
CSL_EDMA3_ADDRMODE_INCR,
CSL_EDMA3_ADDRMODE_INCR );
myParamSetup.srcAddr = (Uint32)mem;//源地址
myParamSetup.aCntbCnt = CSL_EDMA3_CNT_MAKE(4,512);//因为传输的是Uint32，所以每次array跳变是4byte，一共跳变512
myParamSetup.dstAddr = (Uint32)L2+ (0x10000000);//目的地址，L2地址必须用全局地址
myParamSetup.srcDstBidx = CSL_EDMA3_BIDX_MAKE(4,4);
myParamSetup.linkBcntrld= CSL_EDMA3_LINKBCNTRLD_MAKE(0xFFFF,0);//无link
myParamSetup.srcDstCidx = CSL_EDMA3_CIDX_MAKE(0,1);
myParamSetup.cCnt = 1;
if(CSL_edma3ParamSetup(Param1,&myParamSetup) != CSL_SOK)
[
printf ("Error: EDMA Parameter Entry Setup failedn");
]
regionIntr.region = CSL_EDMA3_REGION_GLOBAL;
regionIntr.intr = 0x0003; //中断使能位必须和所设置的TCC相同
regionIntr.intrh = 0x0000;
CSL_edma3HwControl(hModule,CSL_EDMA3_CMD_INTR_ENABLE,®ionIntr);
regionIntr.intr = 0x0000;
CSL_edma3HwChannelControl(hChannel1,CSL_EDMA3_CMD_CHANNEL_SET,NULL);
do [
CSL_edma3GetHwStatus(hModule,CSL_EDMA3_QUERY_INTRPEND,®ionIntr);
] while (!(regionIntr.intr & 0x0001));//
CSL_edma3HwControl(hModule,CSL_EDMA3_CMD_INTRPEND_CLEAR,®ionIntr);
CSL_edma3HwChannelControl(hChannel1,CSL_EDMA3_CMD_CHANNEL_SET,NULL);
do [
CSL_edma3GetHwStatus(hModule,CSL_EDMA3_QUERY_INTRPEND,®ionIntr);
] while (!(regionIntr.intr & 0x0002));//
CSL_edma3HwControl(hModule,CSL_EDMA3_CMD_INTRPEND_CLEAR,®ionIntr);

2楼是我的代码

急啊

注意函数CSL_edma3ChannelOpen的内部实现，其返回值为hEdma = (CSL_Edma3ChannelHandle)pEdmaObj;所以按照你的这种配置顺序，每个channel在调用如下函数open channel时，其输入第一个参数必须不一样，否则返回值只会记录最后一个channel的参数，所以你的代码中在后面enable channel时使能的始终是channel2.
CSL_Edma3ChannelHandle CSL_edma3ChannelOpen
(
CSL_Edma3ChannelObj* pEdmaObj,
CSL_InstNum edmaNum,
CSL_Edma3ChannelAttr* pChAttr,
CSL_Status* pStatus
)