如何强制定时器ISR立即运行？

假设我启动一个时间为1000的计时器。假设计时器的计数初始化为零，计时器的ISR将从现在开始运行1000个计时器，此后每1000个计时器运行1000个计时器。但实际上我希望ISR立即运行*，然后每1000滴答。将计时器的计数初始化为周期（在这种情况下为1000）是实现此目的的一种安全方法吗？它似乎可以工作，但我担心这种技术不是100%可靠的。另一种方法是将定时器ISR的实现移动到一个函数中，从ISR调用这个函数，并且在启动定时器之后立即调用它，但是出于两个原因我不愿意这样做：1）初始化l调用不会在ISR优先级发生，这可能导致行为差异，并且2）函数足够复杂，编译器不会内联它，所以我会在定时器ISR中引起函数调用开销。实验室编译器？我找不到克里斯



      以下为原文

    Suppose I start a timer with a period of 1000. Assuming the timer's count was initialized to zero, The timer's ISR will run 1000 ticks from now, and every 1000 ticks thereafter. But I actually want the ISR to run *immediately*, and every 1000 ticks thereafter. Is initializing the timer's count to the period (1000 in this case) a safe way to accomplish this? It seems to work, but I'm worried that this technique is not 100% reliable.

An alternative would be move the timer ISR's implementation into a function, call this function from the ISR, and also call it immediately after starting the timer, but I'm reluctant to do this for two reasons: 1) the initial call wouldn't occur at ISR priority, which could cause behavioral differences, and 2) the function is complex enough that the compiler won't inline it, so I would incur function call overhead in the timer ISR.

A second question related to this last point: is there a way to force inlining in the MPLABS compiler? I couldn't find one.

Chris