如果在Genesys中使用无源滤波器模板,则可以生成N = 3 - Cauer-Chebyshev,Equal - Full Transform集总元素滤波器。
最终的拓扑是在输入端并联LC与地并联,然后串联并联LC,串联另一个并联LC并在输出端并联LC接地。
输入和输出处的分流
元件是对称的。
我其实想要这个网络的双重性。
在被动模板的最后,我认为没有任何方法可以要求双重模板。
我一直试图弄清楚如何使用S / Filter来实现这种拓扑。
我可以靠近,但我最终得到了过滤器中间的一个或多个元素,我无法摆脱它。
我可以使用无源滤波器输出并使用MathCAD计算双重输出,但它变得乏味。
有人可以带我完成S / Filter的步骤吗?
以上来自于谷歌翻译
以下为原文
If you use the passive filter template in Genesys you can generate an N = 3 - Cauer-Chebyshev, Equal - Full Transform lumped element filter.
Final topology is parallel LC to ground at input, then a parallel LC in series, another parallel LC in series and parallel LC to ground at output.
Shunt elements at input and output are symmetrical.
I actually want the dual of this network. At the end of the passive template I don't think there is any way to ask for the dual.
I have been trying to figure out how to get to this topology with S/Filter. I can get close, but I end up with one or more elements
in the middle of the filter that I can't get rid of.
I can take the passive filter output and compute the dual with MathCAD but it is get
ting tedious.
Can someone walk me through the steps for S/Filter?