你好，蒂亚戈。
对不起，你不明白我。
我想说的是，灵敏度为1mg / LSB的值+/- + 2 +不能以10bit的速度打包。
因为10位数字只能保存0到1023之间的数据。
因此1mg / LSB * 1024 = 1g或仅+/- 0.5g。
但对于+/- 2g的范围，最大振幅信号等于4g。
并且这些4g应该被打包成10位，因此最大灵敏度可能是4g / 1024 = 4mg / LSB。
灵敏度值â€以下为原文
Hello, Thiago.
Sorry, you did not understand me.
I would like to say that the values ​​of + /-2g with sensitivity 1mg/LSB not possible to pack in 10bit.
Because a 10-bit digit can hold data from 0 to 1023 only.
Consequently 1mg/LSB*1024 = 1g or only +/-0.5g.
But for a range of +/-2g, maximum amplitude signal equal to 4g.
And these 4g should be packed into 10bits, hence the maximum of sensitivity is possible 4g/1024 = 4mg/LSB only.
Value of sensitivity ​​are listed in the table on p.10 of the attached document is wrong, and contrary to both the document itself and the experimental data obtained with a real device.
The same document states that:p.17: ''The LIS3DH contains a 10bit, 32-level FIFO.''
p.19: ''LIS3DH embeds a 32-slot of 10bit data FIFO for each of the three output channels, X, Y and Z.''
And I can confidently confirm that the real LIS3DH issue only 10bit data.
