首先，我认为OP有一个空终止的字符串，只是在他的帖子中重新键入错误；否则，他不会得到他发布的结果。@ OP，你的结果的原因是因为你使用了错误的转换函数。ATOI（）函数将字符串转换为16位整数。4294933695的下16位是0x7CBF，符号在分配给未签名的long之前扩展到0x000。7CBF，而4294950495的16位是0xBE5F，符号扩展到0xFFFFEB5F。对于您的输入号，需要使用将字符串转换成32位长整数的AtOLL（）函数。
以上来自于百度翻译
以下为原文
First, I think OP does have a null-terminated string and just retyped wrong in his post; otherwise, he would not get the results that he has posted.
@OP, the reason for your results is because you used the wrong conversion function. The atoi() function converts a character string to a 16-bit integer. The lower 16-bit of 4294933695 is 0x7CBF and sign-extends to 0x00007CBF before assigning to the unsigned long, while the lower 16-bit of 4294950495 is 0xBE5F and sign-extends to 0xFFFFBE5F.
For your input numbers, you need to use the atol() function that converts a string to a 32-bit long integer.
首先，我认为OP有一个空终止的字符串，只是在他的帖子中重新键入错误；否则，他不会得到他发布的结果。@ OP，你的结果的原因是因为你使用了错误的转换函数。ATOI（）函数将字符串转换为16位整数。4294933695的下16位是0x7CBF，符号在分配给未签名的long之前扩展到0x000。7CBF，而4294950495的16位是0xBE5F，符号扩展到0xFFFFEB5F。对于您的输入号，需要使用将字符串转换成32位长整数的AtOLL（）函数。
以上来自于百度翻译
以下为原文
First, I think OP does have a null-terminated string and just retyped wrong in his post; otherwise, he would not get the results that he has posted.
@OP, the reason for your results is because you used the wrong conversion function. The atoi() function converts a character string to a 16-bit integer. The lower 16-bit of 4294933695 is 0x7CBF and sign-extends to 0x00007CBF before assigning to the unsigned long, while the lower 16-bit of 4294950495 is 0xBE5F and sign-extends to 0xFFFFBE5F.
For your input numbers, you need to use the atol() function that converts a string to a 32-bit long integer.
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