我想问的是,如果我用PACKIT3编程,然后拔出PIC
tiT3,那么程序就停止了,这是正确的,因为我没有控制器上的电压,但是如果我把它插上,那么一切都会消失。这是怎么发生的?然后,我必须重新编程,这是不正确的。有人能帮我吗?或者是这样的。
以上来自于百度翻译
以下为原文
What i want to ask is if i program with pickit3 and plug out the pickit3 then the program stops that's correct because i have no voltage on the controller but if i plug it be back in then everything is gone. How does that happen? Then i have to program it again that isn't correct. Can somebody help me? Or is it so.