你好,
这两种方法都是正确的。
让我们假设如下:
扫描时间(有功功率模式)1按钮= TS1
1按钮= TP1的处理时间(有功功率模式)
有功功率模式下的电流=ISP
然后,3个按钮,你可以把它作为扫描Button1,Button1等过程,。或扫描三个按钮,然后,过程中的三个按钮。(即)TS1,TS2、TS3 TP1、TP2,TP3或TS1、TS2、TS3、TP1、TP2,,TP3。
这取决于固件的实现。
谢谢,Shanmathi
以上来自于百度翻译
以下为原文
Hi,
Both the methods are correct.
Let us assume the following:
Scan time (active power mode) for 1 button = ts1
Process time (active power mode) for 1 button = tp1
Current in active power mode = Isp
Then, for 3 buttons, you could either split it as scan button1, process button1 etc.,. or as scan the three buttons and then, process the three buttons. (i.e) ts1, tp1, ts2, tp2, ts3, tp3 or ts1, ts2, ts3, tp1, tp2, tp3.
It depends on your firmware implementation.
Thanks,
Shanmathi
你好,
这两种方法都是正确的。
让我们假设如下:
扫描时间(有功功率模式)1按钮= TS1
1按钮= TP1的处理时间(有功功率模式)
有功功率模式下的电流=ISP
然后,3个按钮,你可以把它作为扫描Button1,Button1等过程,。或扫描三个按钮,然后,过程中的三个按钮。(即)TS1,TS2、TS3 TP1、TP2,TP3或TS1、TS2、TS3、TP1、TP2,,TP3。
这取决于固件的实现。
谢谢,Shanmathi
以上来自于百度翻译
以下为原文
Hi,
Both the methods are correct.
Let us assume the following:
Scan time (active power mode) for 1 button = ts1
Process time (active power mode) for 1 button = tp1
Current in active power mode = Isp
Then, for 3 buttons, you could either split it as scan button1, process button1 etc.,. or as scan the three buttons and then, process the three buttons. (i.e) ts1, tp1, ts2, tp2, ts3, tp3 or ts1, ts2, ts3, tp1, tp2, tp3.
It depends on your firmware implementation.
Thanks,
Shanmathi
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